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anyanavicka [17]

3 years ago

13

What is the inverse of f(x)=x^2-25

2 answers:

Effectus [21]3 years ago

7 0

It is h(x)=3x-6, I really hoped i helped. :)

nirvana33 [79]3 years ago

5 0

F^-1(x)= $\frac{x + 25}{2}$

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stepan [7]

Answer:

$Area = 129.5m^2$

$Perimeter = 48m$

Step-by-step explanation:

Given

See attachment

Required

Determine the area and the perimeter of the garden

Calculating Area

First, we calculate the $area\ of\ the\ rectangle$

$A_1 = L * B$

Where:

$L = 20-(3.5 +3.5)$

$B = 7$

So:

$A_1 = (20 - (3.5 + 3.5)) * 7$

$A_1 = (20 - 7) * 7$

$A_1 = 13 * 7$

$A_1 = 91$

Next, we calculate the area of the two semi-circles.

Two semi-circles = One Circle

So:

$A_2 = \pi r^2$

Where

$r = \frac{7}{2}$

$A_2 = \frac{22}{7} * (\frac{7}{2})^2$

$A_2 = \frac{22}{7} * \frac{49}{4}$

$A_2 = \frac{22}{1} * \frac{7}{4}$

$A_2 = \frac{22*7}{4}$

$A_2 = \frac{154}{4}$

$A_2 = 38.5$

Area of the garden is

$Area = A_1 + A_2$

$Area = 91 + 38.5$

$Area = 129.5m^2$

Calculating Perimeter

First, we calculate the perimeter of the rectangle

But in this case, we only consider the length because the widths have been covered by the semicircles

$P_1 = 2 * L$

Where:

$L = 20-(3.5 +3.5)$

So:

$P_1 =2 * (20-(3.5 +3.5))$

$P_1 =2 * (20-7)$

$P_1 =2 * 13$

$P_1 =26$

Next, we calculate the perimeter of the two semi-circles.

Two semi-circles = One Circle

So:

$P_2 = 2\pi r$

Where

$r = \frac{7}{2}$

$P_2 = 2 * \frac{22}{7} * \frac{7}{2}$

$P_2 = \frac{2 * 22 * 7}{7 * 2}$

$P_2 = \frac{308}{14}$

$P_2 = 22$

Perimeter of the garden is

$Perimeter = P_1 + P_2$

$Perimeter = 26 + 22$

$Perimeter = 48m$

8 0

3 years ago

Monica has 8 more than 3 times the number of marbles Regina has.if Regina has r marbles,how many marbles does Monica have?

jarptica [38.1K]

Monica has +8(3 times (Regina))or

M=8+(3R)

8 0

4 years ago

choose the function correctly identify the transformation of f(x)=x^2 shifted two units down and one unit to the left

julsineya [31]

(x+1)^2-1

...............

3 0

3 years ago

Read 2 more answers

A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.1 ft/s,

pishuonlain [190]

<span>let:
X = the distance of the bottom of the ladder from the wall at any time
dX/dt = rate of travel of the bottom of the ladder = 1.1 ft/sec
A = the angle of the ladder with the ground at anytime
dA/dt = rate of change of the angle in radians per second

X = 10 cos A

dX/dt= -10 sin A dA/dt = 1.1

dA/dt = -1.1/(10 sinA)

When X = 6; cosA = 6/10; sinA = 8/10

Therefore:

dA/dt = -1.1/(10 x 0.8) = -0.1375 radiant per second. </span>

4 0

3 years ago

Help me I am stuck ❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❕❗️

julsineya [31]

Answer:

8. x=-5 and y=7

9. x=-2 and y=0

10. x=-6 and y=-10

11. x=8 and y=-4

12. x=9 and y=-9

13.x=4 and y=10

14. x=5 and y=-7

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers