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amm1812
1 year ago
10

Find the values of the missing sides in the parallelogram given.

Mathematics
1 answer:
natta225 [31]1 year ago
6 0

Given:

m∠B = 44°

Let's find the following measures:

m∠A, m∠BCD, m∠CDE

We have:

• m∠A:

Angle A and Angle B are interior angles on same side of a transversal.

The interior angles are supplementary.

Supplementary angles sum up to 180 degrees

Therefore, we have:

m∠A + m∠B = 180

m∠A + 44 = 180

Subtract 44 from both sides:

m∠A + 44 - 44 = 180 - 44

m∠A = 136°

• m,∠,BCD:

m∠BCD = m∠A

Thus, we have:

m∠BCD = 136°

• m∠CDE:

Angle C and angle CDE form a linear pair.

Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.

Thus, we have:

m∠D = m∠B

m∠D = 44°

m∠CDE + m∠D = 180

m∠CDE + 44 = 180

Subract 44 from both sides:

m∠CDE + 44 - 44 = 180 - 44

m∠CDE = 136°

ANSWER:

• m∠A = 136°

,

•

,

• m∠BCD = 136°

,

•

,

• m∠CDE = 136°

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Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

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0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

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\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

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\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

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\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

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<em>HAVE A NICE DAY</em><em>!</em>

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