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Sever21 [200]
3 years ago
8

choose the function correctly identify the transformation of f(x)=x^2 shifted two units down and one unit to the left

Mathematics
2 answers:
exis [7]3 years ago
5 0

Answer:

The required function is g\left(x\right)=\left(x+1\right)^2-2.

Step-by-step explanation:

The given function is

f(x)=x^2

The general equation is

g(x)=f(x+a)+b

Where, a represents the horizontal shift and b represents the vertical shift.

→ If a>0, then the graph of f(x) shifts left by a units and if a<0, then the graph of f(x) shifts right by a units.

→If b>0, then the graph of f(x) shifts upward by b units and if b<0, then the graph of f(x) shifts downward by b units.

Since the graph of f(x) shifted two units down and one unit to the left, therefore the value of b is -2 and the value of a is 1.

g(x)=f(x+1)+(-2)

g(x)=(x+1)^2-2                         [\because f(x)=x^2]

Therefore the required function is g\left(x\right)=\left(x+1\right)^2-2.

julsineya [31]3 years ago
3 0

(x+1)^2-1

...............
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A recipe calls for 3/4 cup of sugar per batch of cookies. If Gabe wants to make 6 batches of cookies, how many cups of sugar doe
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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
DanielleElmas [232]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.13, 0.168).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

1291 tenth graders, 1098 read above the eighth grade level.

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We want the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level.

So n = 1291, \pi = \frac{193}{1291} = 0.149

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 - 1.96\sqrt{\frac{0.149*0.851}{1291}} = 0.13

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 - 1.96\sqrt{\frac{0.149*0.851}{1291}} = 0.168

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.13, 0.168).

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3 years ago
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