Gravitational pull is determined by ___

Degger [83]

Answer:

Any motion of a body in which gravity is the sole force acting on it is known as free fall. A body in free fall has no force acting on it under general relativity, where gravity is reduced to space-time curvature.

OAmalOHpeO

7 0

3 years ago

An alpha particle travels at a velocity of magnitude 520 m/s through a uniform magnetic field of magnitude 0.034 T. (An alpha pa

Keith_Richards [23]

Answer:

(a) Magnetic force $F=38.584\times 10^{-19}N$

(b) Acceleration $a=5.846\times 10^8m/sec^2$

(C) Speed will remain same

Explanation:

We have given velocity of alpha particle v = 520 m/sec

Magnetic field B = 0.034 T

Charge on alpha particle $q=3.2\times 10^{-19}C$

Mass of alpha particle $m=6.6\times 10^{-27}kg$

Angle between velocity and magnetic field 43°

(a) Force acting on the particle is equal to

$F=q(v\times B)=qvBsin\Theta$

$F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}$

$F=38.584\times 10^{-19}N$

(B) According to newton's law

F = ma. here m is mass and a is acceleration.

So acceleration

$a=\frac{F}{m}=\frac{38.584\times 10^{-19}}{6.6\times 10^{-27}}=5.846\times 10^8m/sec^2$

(c) As the magnetic force is always perpendicular to velocity so speed will remain same neither decreases nor increases.

4 0

3 years ago

If a gas has a gage pressure or 156 kPa, it’s absolute pressure is approximately

Andre45 [30]

Answer: C

Gauge pressure = 156 kPa ,

What is absolute pressure =?

We know that,

absolute pressure = gauge pressure + atmospheric pressure

Pabs = Pgauge + Patm

= 156 + 101.3 (since atm.pr. = 101.3 Kpa)

= 257.3 KPa absoulte

 approximately = 256 KPa absolue

8 0

3 years ago

Why would the kinetic energy at the bottom of the track be less than the potential energy at the top of the track?

sashaice [31]

Answer:

This is because of friction and heat lost.

Explanation:

8 0

3 years ago

Two flat conductors are placed with their inner faces separated by 9mm. If the surface charge density on inner face A is 69 pC/m

ahrayia [7]

Answer:

0.07 V

Explanation:

The electric field between two parallel plates is uniform, and its magnitude is given by

$E=\frac{\sigma}{\epsilon_0}$

where

$\sigma$ is the magnitude of the charge density on each face

$\epsilon_0 = 8.85419 \cdot 10^-12 C^2/Nm^2$ is the vacuum permittivity

In this problem, we have

$\sigma=69 pC/m^2 = 69\cdot 10^{-12} C/m^2$

So, the electric field is

$E=\frac{69\cdot 10^{-12} C/m^2}{8.85419\cdot 10^-12 C^2/Nm^2}=7.79 N/C$

So now we can calculate the potential difference between the two plates, given by:

$\Delta V=E d$

where $d=9 mm=0.009 m$ is the distance between the two plates. Substituting, we find

$\Delta V=(7.79 N/C)(0.009 m)=0.07 V$

5 0

4 years ago

Gravitational pull is determined by ____