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3 years ago

In atoms with only one shell how many electrons are requires for stability?

Physics

1 answer:

Artyom0805 [142]3 years ago

6 0

Answer:

In general, atoms are most stable, least reactive, when their outermost electron shell is full. Most of the elements important in biology need eight electrons in their outermost shell in order to be stable, and this rule of thumb is known as the octet rule.

Explanation:

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Displacement is zero, even though it might have traveled a considerable _____

Brrunno [24]

Displacement is a vector quantity .
So it will be zero if the traveling body comes to the starting point. but it might have traveled a considerable "distance".;-)

3 0

4 years ago

A road perpendicular to a highway leads to a farmhouse located 7 mile away. An automobile traveling on the highway passes throug

Fantom [35]

Answer:

The rate at which the automobile is moving away from the farmhouse is 27.29 m/h.

Explanation:

As shown in the figure, A denotes the position of farmhouse, B be the location of highway intersection and C be the direction along which automobile is moving.

Consider s be the distance between farmhouse and automobile which is represent by AC, x is the distance between intersection and automobile which is represent by BC and the distance between intersection of highway and automobile is represent by AB.

Applying Pythagoras Theorem to the figure,

(AB)² + (BC)² = (AC)²

Since, AB = 7 miles, BC = x and AC = s.

7² + x² = s²

Differentiating both sides of the above equation with respect to time :

$\frac{d}{dt}(7^{2} +x^{2} )=\frac{d}{dt}s^{2}$

$2x\frac{dx}{dt} = 2s\frac{ds}{dt}$

$\frac{x}{s}\frac{dx}{dt}=\frac{ds}{dt}$

$\frac{x}{\sqrt{7^{2}+x^{2} } }\frac{dx}{dt}=\frac{ds}{dt}$

When the automobile is 4 miles past the intersection, i.e.

x = 4 miles and $\frac{dx}{dt}$ = 55 m/h, then

$\frac{4}{\sqrt{7^{2}+4^{2} } }55=\frac{ds}{dt}$

$\frac{ds}{dt}=27.29$ m/h

3 0

3 years ago

Please help me . i need to answer it asap thankyou

alex41 [277]

The amount of heat needed to melt the block of lead is $5.4\cdot 10^4 J$

Explanation:

The amount of heat needed to melt a solid substance already at its melting point is given by the equation

$Q=m \lambda_f$

where

m is the mass of the substance

$\lambda_f$ is the specific latent heat of fusion

In this problem, we have a block of lead already at its melting point, $327^{\circ}C$ . Its mass is

m = 200 g = 0.2 kg

and its specific latent heat of fusion is

$\lambda_f = 2.7\cdot 10^5 J/kg$

Therefore, the amount of heat needed for the block to completely melt is

$Q=(0.2)(2.7\cdot 10^5)=5.4\cdot 10^4 J$

Learn more about specific heat:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

8 0

3 years ago

A hydraulic cylinder causes the distance between points A and O to decrease at a constant rate of 3 inches per second. a) Determ

Ierofanga [76]

Answer:

a) The speed of the slider is 4.28 in/s

b) The velocity vector is 2.33 in/s

Explanation:

a) According to the diagram 1 in the attached image:

$r_{C/A} =12*cos55i-12*sin55j\\r_{C/A}=6.883i-9.829j$

Also:

$v_{C} =v_{A}+w_{AC}*r_{C/A}\\v_{Ci}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC} \\6.883&-9.829&0\end{array}\right]\\v_{Ci}=-3j+(0+9.829w_{AC} i-(0-6.883w_{AC})j\\v_{Ci}=9.829w_{AC}i+(-3+6.883w_{AC})j$

If we comparing both sides of the expression:

$-3+6.883w_{AC}=0\\w_{AC}=0.435rad/s$

$v_{C}=9.829*0.435=4.28in/s$

b) According to the diagram 2 in the attached image:

$r_{C/A}=12cos50i-12sin50j=7.713i-9.192j\\r_{B/C}=-3.856i+4.596j$

$v_{C}=v_{A}+w_{AC}r_{C/A}\\v_{C}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC}\\7.713&-9.192&0\end{array}\right] \\v_{Ci}=-3j+(9.192w_{AC})i+7.713w_{AC}j\\v_{Ci}=9.192w_{AC}i+(7.713w_{AC}-3)j$

Comparing both sides of the expression:

$7.713w_{AC}-3=0\\w_{AC}=0.388rad/s\\v_{C}=3.575i$

$v_{B}=v_{C}+w_{AC}r_{B/C}\\v_{B}=3.57i+\left[\begin{array}{ccc}i&j&k\\0&0&0.388\\-3.856&4.59&0\end{array}\right] \\v_{B}=3.57i+(0-1.78)i-(0+1.499)j\\v_{B}=1.787i-1.499j\\|v_{B}|=\sqrt{1.787^{2}+1.499^{2} } =2.33in/s$

6 0

4 years ago

You are riding your bike to the mall. You travel the first mile in ten minutes. The last mile takes you 15 minutes. This is an e

Valentin [98]

I'm pretty sure it's D. negative acceleration

6 0

3 years ago