I really don't understand what's behind this question at all,
but I can sure do the math:
Speed = (distance covered) / (time to cover the distance) .
= ( 36 meters) / (13 seconds)
= (36/13) (meters/second)
= 2.7692... meters per second (rounded)
(about 6.2 miles per hour) .
Answer:
B. Kinetic energy of the system is partially used up in the deformation of the vehicles.
Explanation:
In an inelastic collision, momentum is conserved, but kinetic energy is not. Kinetic energy is lost as heat or lost in the deformation of the objects.
<h2>
Answer: meteorology </h2>
Explanation:
From the given options , meteorology is the only one that can be studied objectively, since it is an interdisciplinary science that relies on basic sciences such as physics and mathematics and applied sciences to the study of the atmosphere, the weather, the phenomena produced and the physical laws that govern it. In addition, meteorology uses objective techniques to study and predict the various phenomena that occur in the atmosphere.
Unlike history, sociology and theology, in which there is a possibility of the existence of some data are subjective and not true or only based on opinions <u>without scientific evidence</u>.
Answer:
F= 4788 N
Explanation:
Because the car moves with uniformly accelerated movement we apply the following formula:
vf²=v₀²+2*a*d Formula (1)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
d=36.9 m
v₀=14.0 m/s m/s
vf= 0
Calculating of the acceleration of the car
We replace dta in the formula (1)
vf²=v₀²+2*a*d
(0)²=(14)²+2*a*(36.9)
-(14)²= (73.8) *a
a= - (196) / (73.8)
a= - 2.66 m/s²
Newton's second law of the car in direction horizontal (x):
∑Fx = m*ax Formula (2)
∑F : algebraic sum of the forces in direction x-axis (N)
m : mass (kg)
a : acceleration (m/s²)
Data
m=1800 Fkg
a= - 2.66 m/s²
Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :
We replace data in the formula (2)
-F= (1800 kg) * ( -2.66 m/s²
)
F= 4788 N
Answer
given,
Pressure on the top wing = 265 m/s
speed of underneath wings = 234 m/s
mass of the airplane = 7.2 × 10³ kg
density of air = 1.29 kg/m³
using Bernoulli's equation
Applying newtons second law
2 Δ P x A - mg = 0
A = 3.53 m²
