2(s+3)=4s-5
2s+6=4s-5
4s-2s=5+6
2s=11
s=5,5
ANSWER
B(0, 0),
EXPLANATION
The given points are A(−6, 2), B(0, 0), C(4, −2), D(−12, 6), E(−10, 10).
The equation of the direction variation is

The point that belongs the graph of the direct variation must satisfy the variation equation.
Note that the graph of direct variation equation passes through the origin therefore the point (0,0) satisfies it.
0=-12(0)
0=0
This is true
The other points do not satisfy this variation equation, hence they do not lie on its graph
Answer:
144 and 18
Step-by-step explanation:
18 ×24=432÷3=144
Given two functions, we can combine them in such a way so that the outputs of one function become the inputs of the other. ... 3, right parenthesis first and then substitute that result into f f ff to find our answer. ..... Problem 1 ..... end{aligned} (h∘g)(x)=h(g(x))=(g(x))2−2(g(x))=(x+4)2−2(x+4)=x2+8x+16−2x−8=x2+6x+8Define.