Answer:
D’=(3,3); F’=(-2,-2); E’= (-5,0)
Step-by-step explanation:
To find the reflection over the y axis (the line x=0), you just need to change the x either from positive to negactive or the opposite.
Step 1: Factor

1. <span> Multiply 2 by -2, which is -4.</span>
2. <span>Ask: Which two numbers add up to -3 and multiply to -4?
</span>3. <span>Answer: 1 and -4
</span>4. Rewrite

as the sum of

and


Step 2: <span>Factor out common terms in the first two terms, then in the last two terms.
</span>

<span>
Step 3: </span>Factor out the common term


Step 4: Solve for

1. Ask: When will

equal zero?
2. Answer: When

or

3. <span>Solve each of the 2 equations above:
</span>

<span>
Step 5: </span>From the values of

<span>above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2
Step 6: P</span><span>ick a test point for each interval
</span>For the interval

Lets pick

Then,

After simplifying, we get

, Which is false.
Drop this interval.
<span>
For this interval

Lets pick

. Then,

. After simplifying, we get

which is true. Keep this <span>interval.
For the interval </span>

Lets pick

Then,

After simplifying, we get

, Which is false. Drop this interval.
.Step 7: Therefore,

Done! :)</span>
Answer:
4.35 / 100 = 0.0435
Step-by-step explanation:
We find it useful to convert 4.35% to decimal, because if you need to find 4.35% of any number, you can simply multiply that number with 0.0435.
Answer:
Um wat?
Step-by-step explanation:
Answer:
1832 miles
Step-by-step explanation:
First we need to find the angle between the routes of the planes.
If one is N30°W and the other is S45°W, we can find the angle between the routes with the following equation:
30 + angle + 45 = 180
angle = 105°
Then, we need to find the distance travelled by each plane, using the formula:
distance = speed * time
The time is 1.5 hours, so we have that:
distance1 = 800 * 1.5 = 1200 km
distance2 = 750 * 1.5 = 1125 km
Now, to find the distance between the planes, we can use the law of cosines:
distance^2 = 1200^2 + 1125^2 - 2*1200*1125*cos(105)
distance^2 = 3356214.43
distance = 1832 miles