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777dan777 [17]
3 years ago
13

What can you determine about the number of terms of the sum?

Mathematics
1 answer:
ki77a [65]3 years ago
8 0

There are 7 terms in this series.

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The number of State Parks in California is 36 more than one third the number of State Parks in Florida. There are 85 State Parks
mojhsa [17]
The correct answer is 1/3f +36 = 85.  You can figure this out by reading this "<span>The number of State Parks in California is <u>36 more than one third the number of State Parks in Florida</u>" and writing it as an equation.  

85 = <u>1/3f + 36</u></span>
7 0
3 years ago
Consider the matrix. What is |j| ?
Basile [38]

Answer:

- 28

Step-by-step explanation:

Determinant of matrix J is

- 2(5) - 3(6) = - 28

4 0
3 years ago
The ideal gas law takes the form PV=NRT where P represents pressure, V represents volume, N represents number of moles of gas, R
RoseWind [281]
Pv=NRT I think y because it is
5 0
3 years ago
1. Determine the discriminant and nature of roots of each quadratic equation.
Fiesta28 [93]

Answer:

Please check the explanation.

Step-by-step explanation:

The general quadratic equation is

ax²+bx+c=0

The discriminant = D = b² - 4ac

When b² - 4ac = 0 there is one real root.

When b² - 4ac > 0 there are two real roots.

When b² - 4ac < 0 there are two complex roots.

1) x² -6x + 9=0

On comparing with given quadratic equation x² -6x + 9=0

a = 1, b=-6, c=9

D = b² - 4ac

   = (-6)² - 4(1)(9)

   = 36 - 36

   = 0

D = 0

Thus, there is one real root of quadratic equation x² -6x + 9=0.

2) x² -4x + 3=0

On comparing with given quadratic equation x² -4x + 3=0

a = 1, b=-4, c=3

D = b² - 4ac

   = (-4)² - 4(1)(3)

   = 16 - 12

   = 4

D > 0

Thus, there are two real roots of quadratic equation x² -4x + 3=0.

3)  x² -7x - 4=0

On comparing with given quadratic equation x² -7x - 4=0

a = 1, b=-7, c=-4

D = b² - 4ac

   = (-7)² - 4(1)(-4)

   = 49 + 16

   = 65

D > 0

Thus, there are two real roots of quadratic equation x² -7x - 4=0

4)  2x² +3x +5=0

On comparing with given quadratic equation 2x² +3x +5=0

a = 2, b=3, c=5

D = b² - 4ac

   = (3)² - 4(2)(5)

   = 9 - 40

   = -31

D < 0

Thus, there are two complex roots of quadratic equation 2x² +3x +5=0

8 0
3 years ago
Find the coefficient of x^5y^8 in (x+y)^13
Dafna1 [17]

recall that the exponent for the first term will be starting at 13, and descending by one on every expanded term, in the binomial theorem.


so, 13, 12, 11, 10, 9, 8, 7, 6, 5 <---- x⁵ will then be in the 9th term


now, using the "combination" formula to get the coefficient of the 9th term.


k = 8 <--- the 9th term


n = 13 <--- highest exponent


\bf \textit{the coefficient and values of an expanded term} \\\\ (x+y)^{13} \qquad \qquad  \begin{array}{llll} expansion\\ for\\ 9^{th}~term \end{array} \quad  \begin{cases} \stackrel{term}{k}=0..n\\ \stackrel{exponent}{n}\\ -----\\ k=\stackrel{9~term}{8}\\ n=13 \end{cases}


\bf \stackrel{coefficient}{\left(\frac{n!}{k!(n-k)!}\right)} \qquad \stackrel{\stackrel{first~term}{factor}}{\left( a^{n-k} \right)} \qquad \stackrel{\stackrel{second~term}{factor}}{\left( b^k \right)} \\\\\\ \cfrac{13!}{8!(13-8)!}~~x^{13-8}~~(+y)^8\implies 1287~x^5y^8

5 0
4 years ago
Read 2 more answers
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