P=2
Work:
<span><span><span>7p</span>−<span>(<span><span>3p</span>+4</span>)</span></span>=<span><span>−<span>2<span>(<span><span>2p</span>−1</span>)</span></span></span>+10</span></span><span><span><span>7p</span>−<span>(<span><span>3p</span>+4</span>)</span></span>=<span><span>−<span>2<span>(<span><span>2p</span>−1</span>)</span></span></span>+10</span></span><span><span><span>7p</span>+<span><span>−1</span><span>(<span><span>3p</span>+4</span>)</span></span></span>=<span><span>−<span>2<span>(<span><span>2p</span>−1</span>)</span></span></span>+10</span></span><span><span><span><span>7p</span>+<span><span>−1</span><span>(<span>3p</span>)</span></span></span>+<span><span>(<span>−1</span>)</span><span>(4)</span></span></span>=<span><span>−<span>2<span>(<span><span>2p</span>−1</span>)</span></span></span>+10</span></span><span><span><span><span><span><span>7p</span>+</span>−<span>3p</span></span>+</span>−4</span>=<span><span>−<span>2<span>(<span><span>2p</span>−1</span>)</span></span></span>+10</span></span><span><span><span><span><span><span>7p</span>+</span>−<span>3p</span></span>+</span>−4</span>=<span><span><span><span>(<span>−2</span>)</span><span>(<span>2p</span>)</span></span>+<span><span>(<span>−2</span>)</span><span>(<span>−1</span>)</span></span></span>+10</span></span><span><span><span><span><span><span>7p</span>+</span>−<span>3p</span></span>+</span>−4</span>=<span><span><span>−<span>4p</span></span>+2</span>+10</span></span><span><span><span>(<span><span>7p</span>+<span>−<span>3p</span></span></span>)</span>+<span>(<span>−4</span>)</span></span>=<span><span>(<span>−<span>4p</span></span>)</span>+<span>(<span>2+10</span>)</span></span></span><span><span><span>4p</span>+<span>−4</span></span>=<span><span>−<span>4p</span></span>+12</span></span><span><span><span>4p</span>−4</span>=<span><span>−<span>4p</span></span>+12</span></span><span><span><span><span>4p</span>−4</span>+<span>4p</span></span>=<span><span><span>−<span>4p</span></span>+12</span>+<span>4p</span></span></span><span><span><span>8p</span>−4</span>=12</span><span><span><span><span>8p</span>−4</span>+4</span>=<span>12+4</span></span><span><span>8p</span>=16</span><span><span><span><span><span>8p</span>8</span></span></span>=<span><span><span>168</span></span></span></span><span>p=<span>2
Hope this helps:)</span></span>
3x+1 djdjdjdjdidjdjdjfjdjdjdj
Answer:
The answer is "Options A, B, and E represent mutually exclusive events".
Step-by-step explanation:
Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.
In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.
In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.
In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.
In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.
In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.
What are the angles?
if all of them are below 90 degrees, it is acute.
if one angle is 90 degress, it is right
if one angle is more than 90 degrees, it is obtuse
#1
The uniforms are numbered 0, 1, 2, ..., 99. That's 100 numbers. Half of them are odd and half of them are even. So the probability that any one of the uniforms is odd is 1/2 just like the probability that any one uniform is even is 1/2.
(a) The numbers on the uniforms are independent of one another. That is, the number of her cross-country uniform does not in any way determine the number on her basketball uniform and vice versa. This means that we can find the probability that each is odd and multiply these together using what is called the counting principle. The probability that all are odd is:
(1/2)(1/2)(1/2)=1/8
(b) This is done the same way we did part (a). Since the probability of any one uniform being odd is the same as it being even (1/2), the answer here is the same: (1/2)(1/2)(1/2)=1/8
(c) This problem differs from that in (a) and (b). There is only one way for all three uniforms to be odd numbers: (odd, odd, odd) or all even (even, even, even). However, there are multiple ways for the uniforms to be two odd and one even. If the uniforms are listed in order: cross-country, basketball, softball we can get exactly one even in any of three ways:
even, odd, odd
odd, even, odd
odd, odd, even
The probability for any one of these possibilities is (1/2)(1/2)(1/2)=1/8 but since there are three way the probability that we get even exactly once is equal to (3)(1/8) = 3/8
