NEED HELP PLSSSSS

What did you include in your response? Check all that

Fantom [35]

You can pick any of them it won’t hold it against you.
I do it all the time.
Have a good day

4 0

3 years ago

Read 2 more answers

Find the exact solution of -x2 +7x + 5 = 0 by using the Quadratic Formula.

jonny [76]

Answer:

The answer to your question is:

x 1 = -0.65

x2 = 7.65

Step-by-step explanation:

Equation -x² + 7x + 5 = 0

a = -1

b = 7

c = 5

Quadratic formula x = -b ±√(b² -4ac) / 2a

x = - 7 ± √(7² -4(-1)(5) / 2(-1)

x = -7 ± √(49 + 20) / -2

x = -7 ± √69 / -2

x = - 7 ± 8.3 / -2

x1 = -7 + 8.3 / -2 x2 = -7 -8.3 / -2

x 1 = -0.65 x2 = 7.65

7 0

3 years ago

Find the critical value of t for a sample size of 23 and a 99% confidence level. choose the correct value from below:

Kay [80]

We can find critical value by using t - table.
For using t - table we need degree of freedom and alpha either for two tailed test or one tailed test.
We can determine degree of freedom by subtracting sample size from one.
So in given question sample size is 23. So we can say degree of freedom(df) for sample size 23 is
df = 23 - 1= 22
Now we have to go on row for degree of freedom 22.

After that we need to find alpha either for two tailed test or one tailedl test.
Confidence level is 99%. We can convert it into decimal as 0.99.

So alpha for two tailed test is 100 - 0.99 = 0.01

Alpha for one tailed test is 0.01/2 = 0.005.

So we will go on column for 0.01 for two tailed test alpha or 0.005 for one tailed test alpha.
SO the critical value 22 degree of freedom and 0.01 two tailed alpha is 2.819 from t - table.

8 0

3 years ago

PLS HELP!!! 7TH GRADE MATH

Dominik [7]

Answer:

The first picture is 72 ft²

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.31 lb, the mean of all of the weight

a_sh-v [17]

Answer:

a) The difference is of 3.222 lbs.

b) 1.64 standard deviations.

c) Z = 1.64

d) Not significant, as the z-score of 1.64 is between -2 and 2.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of all of the weights is x=2.088 lb, and the standard deviation of the weights is s=1.968 lb.

This means that $\mu = 2.088, \sigma = 1.968$

a. What is the difference between the weight of 5.31 lb and the mean of the weights?

This is $X - \mu = 5.31 - 2.088 = 3.222$

The difference is of 3.222 lbs.

b. How many standard deviations is that [the difference found in part (a)]?

This is the z-score. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.31 - 2.088}{1.968}$

$Z = 1.64$

1.64 standard deviations.

c. Convert the weight of 5.31 lb to a z score.

Z = 1.64, as found above.

d. If we consider weights that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the weight of 5.31 lb significant?

Not significant, as the z-score of 1.64 is between -2 and 2.

5 0

3 years ago