At the end of each year, the amount is (1 + 11%) = 1.11 times the amount at the beginning of the year. When that multiplier is applied 5 times, the result is
$30 * 1.11^5 ≈ $50.55
Answer:
my answer is 2x+ 3y=22 because that the answer
Answer:
a. 5,040 ways
b. 210 ways
Step-by-step explanation:
a) We want to pick 4 numbers out of 10 given that orders matter
If orders do matter, it will be a permutation problem
Mathematically;
n P r = n!/(n-r)!
In this case, n is 10 and r is 4
Thus, we have it that;
10 P 4 = 10!/(10-4)! = 5,040
b) if orders do not matter
It will be a combination problem
n C r = n!/(n-r)!r!
n = 10 and r = 4
10 C 4 = 10! /(10-4)!4!
= 210
A company is selling books. It has to pay $500 to start printing the books, and once they have done that, the books sell at $14.99 each. How many books must they sell to make a profit?
First we would model an equation. X will be the amount of books sold, and Y will be profits (in dollars obv). They had to pay $500 before they could start selling, so we must account for that too.
This equation would be

because for every book sold, X increases by 1, increasing Y by 14.99
The answer would be 34 books sold in order to turn a profit. (500/14.99=
Answer:
D, B, C, A
Step-by-step explanation:
Solve the equations by combining like terms, isolating the variable, and dividing the equation by the coefficient of the variable.
Doing this, the first equation should be 2, the second equation should be -2, the third equation should be -1, and the last equation should be -6.
Then, we can order them.