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krok68 [10]
3 years ago
8

Use synthetic division to solve (x3 + 1) ÷ (x – 1). What is the quotient?

Mathematics
2 answers:
kolbaska11 [484]3 years ago
6 0

The quotient is of the division of {x^3} + 1 and x - 1 \:is \:\boxed{{x^2} + x + 1} and the remainder is \boxed2.

Further explanation:

The numerator of the division is {x^3} + 1 and the denominator isx - 1.

Solve the given polynomial P\left( x \right) = {x^3} + 1 to obtain the quotient by the use of synthetic division.

Now obtain the value of x from the denominator.

\begin{aligned} x - 1&= 0 \\x &= 1\\\end{aligned}

Divide the coefficients of the polynomial by  , to check whether   is a zero of the polynomial.

\begin{aligned}1\left| \!{\nderline {\,{1\,\,\,\,\,\,\,\,\,0\,\,\,\,\,\,\,\,\,\,0\,\,\,\,\,\,\,\,\,1\,} \,}} \right.\hfill \\\,\,\,\,\underline {\,\,\,\,\,\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,\,1}\hfill \\\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,1\,\,\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,2 \hfill\\\end{aligned}

The last entry of the synthetic division told about remainder and the last entry of the synthetic division is 2. Therefore, the remainder of the synthetic division is  .

The entry in the last line of synthetic division gives us the coefficients of the quotient.

The new numbers are the coefficients of the quotient.

The quotient is of the division of {x^3} + 1 \:and \:x - 1 \:is\: \boxed{{x^2} + x + 1} and the remainder is \boxed2.

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Synthetic Division

Keywords: division, synthetic division, long division method, coefficients, quotients, remainders, numerator, denominator, polynomial, zeros, degree.

mamaluj [8]3 years ago
4 0
Steps:

Use the divisor and find x :
x - 1 = 0  **add 1
x= 1
Now we will use the 1 in dividing:

take the coefficients from in front of all terms
   ** make sure you include 0's for x^2 and x since you have to have all terms

set it up with a 1 in a box:

1|  1   0   0  1   **bring the first number down
____________
     1                    **multiply the boxed number by the first number and add it                                 to the second number

1|  1   0   0  1   
____+1_____       **repeat with the rest of the terms
     1   1   

1|  1   0    0    1
  ___+1_+1_+1   
     1   1    1    2                              
**when you're done, use the new numbers to write an equation starting with a term with a degree one less than the previous equation.
**since there is a remainder, rewrite it divided by the original divisor

final answer:
x^2 + x + 1 + (2/ x -1)
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the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

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