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kondor19780726 [428]
3 years ago
14

The revenue of Apple® went from $54.5 billion in 2013 to $74.6 billion in 2015. Find an exponential function to model the revenu

e as a function of years since 2013. What is the continuous percent growth rate, per year, of revenue?
Round your answer to three decimal places.
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0

74.6 - 54.5 = 20.1

20.1/2 = 10.05

54.5/74.6 = 0.731 (rounded)

Apple makes 10.05 billion more every year. The percent growth rate is about 73.1% a year.

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HELP ASAP SOS!!! <br> QUESTION : write a 4 step proof that triangle ABD is congruent to ABD
SCORPION-xisa [38]

Here are a few reasons:

The triangles have the same three sides

The triangles have the same three angles

The triangles could perfect overlap one another

They have corresponding angles.

Not sure if this helped but I hope so!

8 0
3 years ago
Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut
frozen [14]

Answer:

a)\sqrt{144-288t+208t^2} b.) -12knots, 8 knots c) No e)4\sqrt{13}

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

a)

We know that at time t , the ship A has moved 12\dot t (n.m) and ship B has moved 8\dot t (n.m). We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}

b)

We want to find \frac{ds}{dt} for t=0 and t=1

\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots

c)

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0

Since function f(x)=199-288x+208x^2 is quadratic, concave up and has no real roots, we know that 199-288x+208x^2>0 for every t. So, the ships haven't seen each other.

d)

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

e)

Function ds/dt has a horizontal asympote in the first quadrant if

                                                \lim_{t \to \infty} \frac{ds}{dt}

So, lets check this limit:

\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}

Notice that:

4\sqrt{13}=\sqrt{12^2+5^2}=√(speed of ship A² + speed of ship B²)

5 0
3 years ago
Help me once more please
Damm [24]
The graph that Franco is Incorrect
It suppose to be from left to right
5 0
3 years ago
There are 6 sixth graders , 7 seventh graders , and 8 eight graders entered in a contest.
fgiga [73]

Answer:

See below ~

Step-by-step explanation:

<u>P (6th grader)</u>

  • No. of 6th graders / Total students
  • 6 / 6 + 7 + 8
  • 6/21
  • 2/7

<u>P (6th grader after)</u>

  • No. of 6th graders - 1 / Total students - 1
  • 6 - 1 / 21 - 1
  • 5/20
  • 1/4

<u>Question 1 : P (Both 6th graders)</u>

  • P = P (6th grader) × P (6th grader after)
  • P = 2/7 x 1/4 = 2/28 = <u>1/14</u>

<u></u>

<u>Question 2 : P' (Both 6th graders)</u>

  • P' = 1 - P
  • P' = 1 - 1/14
  • P' = <u>13/14</u>
4 0
2 years ago
Read 2 more answers
a pack of toilet paper was originally $4.50 , it now cost $6.75. What is the solution to this problem?
Nitella [24]
2.25 is correct have a good day
5 0
2 years ago
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