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weqwewe [10]
3 years ago
7

Identify any zeros of y = x2 + 4x + 5

Mathematics
2 answers:
pav-90 [236]3 years ago
6 0

Answer:

<h2>B. There are no zeros</h2>

Step-by-step explanation:

\text{The zeros for y = 0:}

x^2+4x+5=0\qquad\text{subtract 5 from both sides}\\\\x^2+2(x)(2)=-5\qquad\text{add}\ 2^2\ \text{to both sides}\\\\x^2+2(x)(2)+2^2=-5+2^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+2)^2=-5+4\\\\(x+2)^2=-1

Andrei [34K]3 years ago
4 0

Answer:

B. There are no zeros

Step-by-step Explanation:

None of the given point even lie on the parabola (curved line) of the graph, so they can't possibly be zeros. The only explanation is that there simply aren't any zeros.

So your answer is...B. There are no zeros.

Hope this helps!

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