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charle [14.2K]
3 years ago
13

Can someone help me with this question please?

Mathematics
1 answer:
Solnce55 [7]3 years ago
5 0
5x^2-(2x-3)^2x
=5x^2+-4x^2+12x+-9
=5x^2+-4x^2+12+-9
=(5x^2+4x^2)+(12x)+(-9)
=x^2+12x+-9

the final answer is..... x^2+12x-9

I hope this helps you out.
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The sum of 2 consecutive integers is one less than 3 times the smaller integer find the 2 integers
aalyn [17]

The two consecutive integers are 2 and 3

<em><u>Solution:</u></em>

Let x and x + 1 are the two consecutive integers

Let "x" be the smallest integer

Let "x + 1" be the larger integer

<em><u>Given that, sum of 2 consecutive integers is one less than 3 times the smaller integer</u></em>

Therefore,

sum of 2 consecutive integers = one less than 3 times the smaller integer

sum of 2 consecutive integers = 3 times the smaller integer - 1

x + x + 1 = 3(x) - 1

2x + 1 = 3x - 1

3x - 2x = 1 + 1

x = 2

Thus the smaller integer = x = 2

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4 years ago
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Stolb23 [73]

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3 years ago
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Rasek [7]

Answer:

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Step-by-step explanation:

6 0
4 years ago
When the function f(x) = 3(5)x is changed to f(x) = 3(5)x + 22, what is the effect?
Alex787 [66]

Answer:

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Step-by-step explanation:

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3 years ago
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s344n2d4d5 [400]

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Step-by-step explanation:

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