Answer:
Mildred is correct because she distributed 5 correctly
Step-by-step explanation:
We cannot tell exactly which solution goes with which student, but we believe you are saying ...
Mildred’s Solution:
5 (Negative 2 and one-fourth) = 5 (negative 2 minus one-fourth)
= negative 10 minus StartFraction 5 over 4 EndFraction
= negative 11 and one-fourth
This solution describes the correct distribution of 5. Whoever it belongs to gave the correct solution.
Use elimination
Multiply first equation by 4
12a - 8b = 56
12a + 9b = 39
Subtract both
-17b = 17
b = -1
Plug in -1 for b
3a - 2(-1) = 14
3a = 12, a = 4
Final answer: a = 4, b = -1
2 consecutive even integers : x and x + 2
x + x + 2 = 170
2x + 2 = 170
2x = 170 - 2
2x = 168
x = 168/2
x = 84
x + 2 = 84 + 2 = 86
so ur 2 numbers are 84 and 86
Use the Pythagorean theorem to find z:
z = √(6^2 + 9^2)
z= √(36 + 81)
z = √117
z = 3√13 = 10.8
Use leg rule to find x:
x/6 = 6/9
Cross multiply:
9x = 36
Divide both sides by 9:
x = 36/9
x = 4
Use Pythagorean theorem to find y:
y = √(6^2 + 4^2)
y= √(36 + 16)
y = √52
y = 2√13 = 7.2
Answer:
Step-by-step explanation:
We are going to use the identity
because this identities right hand side matches your expression where
and 
.
So we have that 
is equal to .
