We are given <span>μ > 1180 </span><span>α = 0.02 </span><span>σ = 201.71 x = </span><span>1198.79 n = 200
The null hypothesis is </span>μ ≤ 1180 while the alternative hypothesis is μ > 1180 The test statistic is 1.32 which means that the confidence internval is 98%. Getting the z-score z = (x - μ) / σ z = (1198.79 - 1180) / 201.71 z = 0.093
For a normally distributed population, the z-score of 0.093 has a p-value of p = 0.46
