If it's addition you do the opposite which is subtraction and that's the answer that you get so 6m_2=m+13 so add 6-2=4 and then 13-4=9
We need to find the surface area of the solid.
Since it's formed by cubes with edges of 1 meter, each square on the surface of the solid has an area equal to:

Thus, to find its surface area, we need to count the number of squares on its surface, and then multiply this number by 1 meter².
We can see that this solid has two equal latera surfaces (right and left). Each one of them has 17 squares.
Also, the number of squares on the horizontal surfaces is the same on the top and bottom of the solid. Each one of them has 10 squares.
And the vertical surfaces on the front and back of the solid have the same number of squares: 8 squares each.
Then, adding those quantities and multiplying the result by two, we find the total number of squares on the surface of the solid:

Therefore, the surface area of the solid is 70 m².
We have been given two inequalities
and
. We are asked to find the integers that satisfy both inequalities.
Let us solve for our 1st inequality.




Upon combining our both inequalities, we will get:

This means that solution of our inequalities is x values greater than
and less than
.
We know that integers between
and
are:
.
Therefore, our solution would be
.