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alina1380 [7]
3 years ago
5

What is the absolute value of -8? Use the number line to help answer the question.

Mathematics
2 answers:
aev [14]3 years ago
6 0

Answer:

its 8

Step-by-step explanation:

because you take away the negative sign

SSSSS [86.1K]3 years ago
3 0

Answer:

is 8

Step-by-step explanation:

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The photo will explain

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Please solve these coin problems:
ratelena [41]
1)
Solving from system of equations:
x- amount of 1 cent stamps
y- amount of 33 cent stamps
\left \{ {{1*x+33*y=18,40} \atop {x+y=80}} \right.\\x=80-y\\0,01*(80-y)+0,33y=18,40\\0,8-0,01y+0,33y=18,40\\0,32y=18,40-0,8\\0,32y=17,60 /:0,32\\y=55\\x=80-55=25
2)
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From system of equations:
\left \{ {{0,2x+0,34y=19,90} \atop {x+y=75}} \right.\\x=75-y\\0,2(75-y)+0,34y=19,90\\ 15-0,2y+0
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6 0
3 years ago
Help need plz thx ASAP
pychu [463]
Choose D
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8 0
3 years ago
Can you help me graph and list the (Zeros, Maximums, Minimums, Asymptotes)
Marina86 [1]

The zero of the function is at 33.69 degree , the graph is plotted and attached with the answer.

<h3>What is a Function ?</h3>

A function is a law that relates a dependent variable and an independent variable with each other

It is given that

y = 2tan (x - π/2) +3

To find the zeroes of a function that function has to be equated to zero.

2tan (x - π/2) +3 = 0

2tan (x - π/2)  = -3

tan (x - π/2)  = -3/2

x - 90 = -56.31

x = 33.69 degree

The zero of the function is at 33.69 degree

For finding the maxima /minima

the derivative is

dy/dx = 2 sec² (x - π/2)

the point at which the slope is zero is substituted in the second derivative to find maxima/minima

d²y/dx² = 4 sec² (x - π/2) tan (x - π/2)

if the value is negative then it is a maxima and if it is positive it is a minima.

The vertical asymptote is found by finding the values that make the function undefined

x = 0+ πn

No horizontal or oblique asymptote

To know more about Function

brainly.com/question/12431044

#SPJ1

5 0
1 year ago
Translated up by 1 unit
kkurt [141]

Answer:

no

Step-by-step explanation:

no enough info

8 0
2 years ago
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