The problem statement describes the dimensions. The base length is 15 ft; the height is 10 ft.
The area of a parallelogram is the product of base length and height, just as it is for a rectangle.
A = bh
A = (15 ft)(10 ft) = 150 ft²
Mr Morris should purchase 150 ft² of material.
_____
If you compare the area to a 15 ft by 10 ft rectangle, you see the "excess" triangle at the left end just matches the "missing" triangle at the right end. The A=bh formula still works even if the top and base are offset by more than the width of the base.
-3x/2 + 5 would be equivalent.
Answer:
Strictly speaking, there is not enough information to solve the problem.
If we assume m<EFY = 90, then:
m<DEY = 29
m<DEF = 58
Step-by-step explanation:
Going by the exact information shown, the answer is really that there isn't enough information to answer the question.
On the other hand, if angle EFY is a right angle, then we have two right triangles that can be proved congruent by HL. Then by CPCTC, angles DEY and FEY are congruent. We set their measures equal and solve for y.
4y - 7 = 2y + 11
2y = 18
y = 9
m<DEY = 4y - 7 = 4(9) - 7 = 36 - 7 = 29
m<DEF = 2m<DEY = 2(29) = 58
Answer:
518400, I think. I dunno for sure....
Answer:
200,000,000 + 8,000,000 + 10,000 + 400 + 70 + 8
Step-by-step explanation:
i think, i am sorry if i am incorrect