Given:
Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².
To find:
The area of the smaller jug.
Solution:
If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.
Two jugs are similar. So,
Therefore, the area of the smaller jug is about 55.56 cm².
Answer:
1/(x^(17/12)y^(5/3))
Step-by-step explanation:
We assume you want to simplify the expression. The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
Using these "all at once", we can add up the exponents of each of the variables:
x^(-2/3 -2·0 -(1/2)(3/2))·y^(-2/3-(1/2)·2) = x^(-2/3-3/4)y^(-2/3-1)
= x^(-17/12)y^(-5/3)
= 
Price for company A:
p(A) = 10 + 5*h
Price for company B:
p(B) = 7*h
,where h is the hours.
To find the hours after which the prices for both are going to be the same, we set the price for A equal to the price of B and calculate h.
10 + 5*h = 7*h <=>
2*h = 10 <=>
h = 10/2 <=>
h = 5 hours
A.) Both services will cost the same if it is for a 3 hours service.
B.) 16+9X=20+7X.
=>9x-7x=20-16.
=>2x=4.
=>x=4/2.
=>x= 2.
because its isosceles so 9+9=x²
and x equal
2√3
