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Georgia [21]
3 years ago
11

7. Given b= 4, c = 10, and A = 34 degrees, use the Law of Cosines to solve for a. Round your answer to the nearest whole number.

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:  (7) 7.0              (8) 17.3            (9) 64.7°

<u>Step-by-step explanation:</u>

Law of Cosines is: a² = b² + c² - 2bc · cos A

                         or: b² = a² + c² - 2ac · cos B

                         or: c² = a² + b² - 2ab · cos C

7) b = 4, c = 10, ∠A = 34

a² = b² + c² - 2bc · cos A

   = 4² + 10² - 2(4)(10) · cos 34°

   = 16 + 100 - 80 (0.829)

   = 116 - 66.323

   = 49.677

a = \sqrt{49.677}

a = 7.0

8) a = 11, b = 8, ∠C = 131

c² = a² + b² - 2ab · cos C

   = 11² + 8² - 2(11)(8) · cos 131°

   = 121 + 64 - 176 (-0.656)

   = 185 + 115

   = 300

c = \sqrt{300}

c = 17.3

9) a = 10.5, b = 5.9, c = 9.6

9.6² = 10.5² + 5.9² - 2(10.5)(5.9) · cos C

92.16 = 110.25 + 34.81 - 2(10.5)(5.9) · cos C

92.16 = 145.06 - 123.9 cos C

-52.9 = -123.9 cos C

0.427 = cos C

cos⁻¹ (0.427) = C

64.7° = C

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Plz, help!!!! :[ <br> I don't know the answer<br> look at the pic
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Answer:

174 in²

Step-by-step explanation:

(A1)= 9(5)= 45 in²

(A2)= 3(5)=15 in²

(A3)= 3(5)=15 in²

(A4)= 9(3)= 27 in²

(A5)= 9(5)= 45 in²

(A6)= 9(3)= 27 in²

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6 0
3 years ago
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

6 0
3 years ago
Given the function f(x) = -3x2 + 4x + 6, find f(2) and f(3). Choose the statement that is true concerning these two values.
denis23 [38]

Answer:

The value of f(2) is larger than the value of f(3).

Step-by-step explanation:

f(x) = -3x^{2} +4x+6\\f(2) = -3*2^{2} +4*2+6=2\\f(3) = -3*3^{2} +4*3+6=-9\\

3 0
3 years ago
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