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nignag [31]
3 years ago
10

A college student borrows $1,000 for 9 months to pay for a semester of school. if the interest is $61.88, find the monthly payme

nt
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

In the question , it is given that , a college student borrows $1,000 for 9 months to pay for a semester of school.

And the interest is $61.88 .

Let the monthly payment be $x . So in 9 months, the student paid $9x .

And interest is the difference of 9x and the money borrowed, that is

9x - 1000 = 61.88

Adding 1000 to both sides

9x = 1061.88

x = \frac{1061.88}{9} =$117.99

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krok68 [10]

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Step-by-step explanation:

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3 years ago
Consider w=sqrrt2/2(cos(225°) + isin(225°)) and z = 1(cos(60°) + isin(60°)). What is w+ z expressed in rectangular form?
SVETLANKA909090 [29]

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Option (3)

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w = \frac{\sqrt{2}}{2}[\text{cos}(225) + i\text{sin}(225)]

Since, cos(225) = cos(180 + 45)

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sin(225) = sin(180 + 45)

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Therefore, w = \frac{\sqrt{2}}{2}[-\frac{\sqrt{2}}{2}+i(-\frac{\sqrt{2}}{2})]

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z = 1[cos(60) + i(sin(60)]

  = [\frac{1}{2}+i(\frac{\sqrt{3}}{2})

  = \frac{1}{2}(1+i\sqrt{3})

Now (w + z) = -\frac{1}{2}(1+i)+\frac{1}{2}(1+i\sqrt{3})

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                   = \frac{(\sqrt{3}-1)i}{2}

Therefore, Option (3) will be the correct option.

3 0
3 years ago
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