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Lana71 [14]
3 years ago
10

Given the Arithmetic sequence A1,A2,A3,A4A1,A2,A3,A4

Mathematics
1 answer:
Bad White [126]3 years ago
7 0
The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59

This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.

The n-th term is
a_{n}=a_{1}+(n-1)d
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
     = 29 + 320
     = 349

Answer: a₃₃ = 349
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