Question

Given the Arithmetic sequence A1,A2,A3,A4A1,A2,A3,A4

Answer 1

The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59

This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.

The n-th term is
$a_{n}=a_{1}+(n-1)d$
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
     = 29 + 320
     = 349

Answer: a₃₃ = 349