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Jet001 [13]
3 years ago
7

What is the missing reason in the proof ?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0

Answer:

A

Step-by-step explanation:

The reflexive property of congruence basically says that a segment is congruent with itself. B and C are related to angles so do not apply here.

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6.3 x 10^14<br><img src="https://tex.z-dn.net/?f=6.3%20%5Ctimes%20%20%7B10%7D%5E%7B14%3F%7D%20" id="TexFormula1" title="6.3 \tim
Nutka1998 [239]

I'm assuming you're looking to find the expanded form of the number?

This number is in scientific notation. The easiest way to convert it to a normal number is to move the decimal place 14 to the right. I've attached a picture showing how to do this. You should get 630,000,000,000,000

There's a faster way to do this - notice that you need to move the decimal 14 to the right, and there's one number already after the decimal place. Therefore, 13 places will be filled with zeros. So, just write out 63 and add 13 zeros.

For more general help on scientific notation, check out these videos: https://www.khanacademy.org/math/pre-algebra/pre-algebra-exponents-radicals/pre-algebra-scientific-notation/v/scientific-notation-old

Hope that helps! Feel free to message me or leave a comment if I can clarify anything :)

7 0
3 years ago
Last year, a widget factory produced one million,twele thousand, sixty widgets. What is the nunber in standard form
aivan3 [116]
1,012,060 this is it in standard form
6 0
2 years ago
Read 2 more answers
A box in the shape of a right rectangular prism has a length of 8.5 inches, a width of 4.5 inches, and a height of 3.75 inches,
jeyben [28]
Just multiply all of them because Volume = Length x Width x Height. So it's 8.5 x 4.5 x 3.75. That equals 143.4375. Cubic inches is just there after you multiply, so you don't have to convert anything. So it's 143.4375 cubic inches.
6 0
3 years ago
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Help with this pls and thank u
stira [4]

Answer:

where is the question plsss tell me what you ask

8 0
2 years ago
If a point is equidistant from the endpoint of segment, then it is
Mashutka [201]

Hi

.... then it is  located on the perpendicular bisector.

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