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Oxana [17]
3 years ago
8

Please help me i dont understand/bad at graphs

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
5 0
I'm think its a cause its the only one I can see that's lines up with (0,5)
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At an ice cream parlor ,ice cream cones cost $1.10 and sundaes cost $2.35 one day the receipts for a total of 172 cones and sund
LUCKY_DIMON [66]

88 cones were sold.

Step-by-step explanation:

Let,

Cones = x

Sundaes = y

Cost of one cone = $1.10

Cost of one sundae = $2.35

According to given statement;

x+y=172 Eqn 1

1.10x+2.35y=294.20 Eqn 2

Multiplying\ Eqn\ 1\ by\ 1.10\\1.10x+1.10y=189.2\ Eqn\ 3\\Subtracting\ Eqn\ 3\ from\ Eqn\ 2\\(1.10x+2.35y)-(1.10x+1.10y)=294.20-189.2\\1.10x+2.35y-1.10x-1.10y=105\\1.25y=105\\Dividing\ both\ sides\ by\ 1.25\\\frac{1.25y}{1.25}=\frac{105}{1.25}\\y=84

Putting value of y in Eqn 1;

x+84=172\\x=172-84\\x=88

88 cones were sold.

Keywords: Linear equations, multiplication

Learn more about linear equations at:

  • brainly.com/question/10666510
  • brainly.com/question/10699220

#LearnwithBrainly

3 0
3 years ago
What is the gcf of 6,16
AVprozaik [17]

2 would be the gcf

have a nice day:)

hoped this helped you

7 0
3 years ago
Which statement about the solution of the inequality k<-3 1/4 is true?
Juliette [100K]

Answer: Last option

The number -8.4 is a solution to the inequality because -8.4 is located to the left of -3\frac{1}{4} on the number line.

Step-by-step explanation:

Note that: -3\frac{1}{4} =-3-\frac{1}{4} =-3.25

The inequality is:

k

The inequality is:

This means that the inequality includes all values of the number line that are less than -3.25 or that are to the left of -3.25

__-8.4_________-3.25_-3____0___0.9____________7.1__

Note that the number -8.4 is less than -3.25, because it is to its left on the number line.

Then the correct statement is:

The number -8.4 is a solution to the inequality because -8.4 is located to the left of -3\frac{1}{4} on the number line.

4 0
3 years ago
Read 2 more answers
I have no clue Someone Please Help!!!!!
erma4kov [3.2K]

Answer:

D

Step-by-step explanation:

we have to see the value of y on x=-2

which is 2

so g(-2)=2

7 0
3 years ago
I know you’re supposed to change the bounds and break up the integral, but for some reason, I can’t get the 44/3. Can someone ex
tatyana61 [14]

First, look for the zeroes of the integrand in the interval [0, 6] :

x² - 6x + 8 = (x - 4) (x - 2) = 0   ⇒   x = 2   and   x = 4

Next, split up [0, 6] into sub-intervals starting at the zeroes we found. Then check the sign of x² - 6x + 8 for some test points in each sub-interval.

• For x in (0, 2), take x = 1. Then

x² - 6x + 8 = 1² - 6•1 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

• For x in (2, 4), take x = 3. Then

x² - 6x + 8 = 3² - 6•3 + 8 = -1 < 0

so x² - 6x + 8 < 0 over this sub-interval.

• For x in (4, 6), take x = 5. Then

x² - 6x + 8 = 5² - 6•5 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

Next, recall the definition of absolute value:

|x| = \begin{cases}x & \text{for }x \ge0 \\ -x & \text{for }x < 0\end{cases}

Then from our previous analysis, this definition tells us that

|x^2 - 6x + 8| = \begin{cases}x^2 - 6x + 8 & \text{for }0

So, in the integral, we have

\displaystyle \int_0^6 |x^2-6x+8| \, dx = \left\{\int_0^2 - \int_2^4 + \int_4^6\right\} (x^2 - 6x + 8) \, dx

Then

\displaystyle \int_0^2 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_0^2 = \frac{20}3 - 0 = \frac{20}3

\displaystyle \int_2^4 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_2^4 = \frac{16}3 - \frac{20}3 = -\frac43

\displaystyle \int_4^6 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_4^6 = 12 - \frac{16}3 = \frac{20}3

and the overall integral would be

20/3 - (-4/3) + 20/3 = 44/3

3 0
3 years ago
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