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3 years ago

Please help me i dont understand/bad at graphs

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

5 0

I'm think its a cause its the only one I can see that's lines up with (0,5)

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Convert 8/20 to a percent

nikitadnepr [17]

Answer:

40%

Step-by-step explanation:

8/20

Divide it to get a decimal.

8/20 = 2/5 = 0.4

Change the decimal into a percent by moving the decimal point 2 places to the right.

0.4 = 40%

7 0

3 years ago

Dimension of a cuboid is 4 m 3 m ad 5 m how many such cuboid can form a cube....... please and urgent..experts please help

larisa [96]

Step-by-step explanation:

We dimension of the smallest cube to be made from cuboids of sides 3 m , 4 m and 5 m will be the least common multiple of 3 m, 4 m and 5 m i.e. 60 m

12 cuboidal should be stacked along 5 m edge to 60 m, 15 cuboids should be stacked along 4 m edge and 20. cuboids should be stacked along edge to make a cube of 60 m edge, Hence number of cuboids are 12× 15 ×20=3600

hope it helps

4 0

3 years ago

A researcher wishes to find out whether giving a student $1 million in cash will improve or ruin the student's grades in school.

shepuryov [24]

Answer:

Harry,Greta,William,Hiroshi

Step-by-step explanation:

Apex :)

6 0

3 years ago

A submarine at 21 feet below sea level suddenly moves up about 6 feet. At what depth is

Artist 52 [7]

Answer:

The submarine is 15 feet below sea level.

Step-by-step explanation:

7 0

3 years ago

The diagram shows the sector of a circle with the centre O and radius 6cm.

cricket20 [7]

Answer:

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN = $\frac{\theta}{360}(\pi r^{2})$

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN = $\frac{50}{360}(\pi )(6)^2$

= 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN = $\frac{1}{2}(OP)(PN)$

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) = $\frac{PN}{ON}$

PN = ONsin(25°)

= 6sin(25°)

= 2.536 cm²

cos(25°) = $\frac{OP}{ON}$

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

= 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

≈ 1.92 cm²

3 0

3 years ago