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3 years ago

Which situation represents a proportional relationship?

Mathematics

2 answers:

BaLLatris [955]3 years ago

7 0

Answer:

I think its A) The cost of purchasing grapefruit for $1.80 per pound with a coupon for $1.00 off the total cost because a proportional has to be based or the same .

Step-by-step explanation:

drek231 [11]3 years ago

4 0

I believe it’s the last one.

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Select the correct answer from each drop-down menu. In the coming year, a vehicle manufacturer has decided to manufacture 150 ve

dezoksy [38]

Answer:

Given:

v = 150d

v represents company's production for the coming year

d represents the number of days

150 is the daily production

The rate of change of the function representing the number of vehicles manufactured for the coming year is CONSTANT (150) , and its graph is a STRAIGHT LINE . So, the function is a LINEAR function.

Step-by-step explanation:

7 0

2 years ago

Topic: Area of non shaded area.

Dimas [21]

Answer:B) 150

Step-by-step explanation:

Area of rec= L×W

= 10×30= 300

Area of shaded area= 1/2 Base× Height

1/2×10×15=75

75×2 = 150

Area of unshaded part= 300-150= 150

8 0

3 years ago

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14. Find the value of x if QS bisects PQR and<br> mZPQR = 82.<br> (10.x + 1)<br> S<br> R

Bumek [7]

Maybe S I’m not sure

4 0

3 years ago

Read 2 more answers

PLEASE HELP DUE TODAY 50 POINTS

Alchen [17]

This is simple proportions, because of their similarity:

$\frac{13}{38.6} = \frac{10}{x}$

$x = \frac{386}{13}$

8 0

3 years ago

Read 2 more answers

Reflect quadrilateral CJKM across the y-axis. Find the location of K'.

Montano1993 [528]

$K(1,4)\rightarrow K^{\prime}(-1,4)$

Explanation

Step 1

find the coordinate of every point of the quadrilateral

C(-3,1)

J(0,1)

K(1,4)

M(4,-2)

Step 2

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).

$(x,y)\rightarrow reflect\text{ across y -Ax is}\rightarrow(-x,y)$

therefore

$\begin{gathered} C\mleft(-3,1\mright)\rightarrow C^{\prime}(3,1) \\ J\mleft(0,1\mright)\rightarrow J^{\prime}(0,1) \\ K\mleft(1,4\mright)\rightarrow K^{\prime}(-1,4) \\ M(4,-2)\rightarrow M^{\prime}(-4,-2) \end{gathered}$

so, the answer is

$K^{\prime}(-1,4)$

i hope this helps you

4 0

1 year ago