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wariber [46]
3 years ago
7

Which situation represents a proportional relationship?

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

Answer:

I think its A) The cost of purchasing grapefruit for $1.80 per pound with a coupon for $1.00 off the total cost because a proportional has to be based or the same .

Step-by-step explanation:

drek231 [11]3 years ago
4 0
I believe it’s the last one.
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PLEASE HELP!!! I know it’s a lot of questions but I’m just trying to get this done, but I can’t because I’m clueless. I tried gr
artcher [175]

Answer:

a) The graph shifted to the left by 3 units and up 1 unit.

b) Domain = x ∈ R    Range = y ∈ R

(Domain (x) = All real numbers     Range (y) = All real numbers)

c) (-4, 0)

d) (0, 2.442)

~Hope this helps! If you have any questions, please let me know!~

6 0
3 years ago
2. Dr. Scott bought 3 pound of oranges for $1.50. How much would 7
n200080 [17]

Do 1.50 divided by 3 to get the unit price.

6 0
3 years ago
Will give brainliest. Explain in detail please!
Zina [86]

Answer:

p < -28

Step-by-step explanation:

This is a simple solve - all we have to do is treat it like a normal equation and solve for p.  This involves only one step - subtract 4 from both sides.  We now end up with p < -28.  And there you are!

8 0
3 years ago
Read 2 more answers
What is the LCM of 10 and 14
Oduvanchick [21]
The LCM of 10 and 14 is 2.
5 0
3 years ago
Read 2 more answers
The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac
olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
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