Answer:
There should be at most 24 lucky numbers in the third bag.
Step-by-step explanation:
Initially, there are 200 numbers. Two bags with 100 each. There are 31+18 = 49 lucky numbers. So there is a 49/200 = 0.245 probability that a randomly selected number from a random bag is the lucky number.
Now with 300 numbers, we want this probability to be lower than 24.5%. So we should solve the following rule of three:
200 - 49
300 - x
With the third bag, the probability will be the same if 73.5-49 = 24.5 lucky numbers are added. So there should be at most 24 lucky numbers in the third bag.
Answer:
a
Yes
b
c
d
Step-by-step explanation:
From the question we are told that
Two fair dice, one green and one red were rolled
Generally the outcomes on the dice independent because the outcome on the first dice is not affected by the second die
Generally the probability of getting a 1 on a dice rolled is 
the probability of getting a 5 on a dice rolled is 
Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as
Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as
Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as
Which of the following is a geometric sequence? A. 1, 1, 2, 3, 5, ... B. 2, 4, 6, 8, ... C. 7, 4, 1, -2, ... D. 1, ½, ¼, ⅛
Nonamiya [84]
A geometric sequence is when each term is found by multiplying the previous term by a constant. in this case, the answer is D because each term is being multiplied by 0.5, hope this helps!
Answer:
1. -13
2. 8
Step-by-step explanation:
39 / -13 = 3
-64 / 8 = -8
Hope this helps!!!
