Answer is B hope it helps
we know that
The simple interest formula is equal to

where
P is the Principal amount of money to be invested
I is the amount of money in interest
r is the rate of interest
t is Number of Time Periods
in this problem we have

substitute in the formula above and solve for P

![P=14.65/[(0.025)(2)]](https://tex.z-dn.net/?f=P%3D14.65%2F%5B%280.025%29%282%29%5D)

therefore
<u>the answer is</u>

Answer:
Step-by-step explanation:
11.04 = 10(1.02)^n
1.104 = 1.02^n
ln 1.104 = ln 1.02^n
ln 1.104 = n ln 1.02
n = ln 1.104/ ln 1.02
n = 4.99630409516
4.99 can be rounded to 5.
So a reasonable domain would be 0 ≤ x < 5
PART B)
f(0) = 10(1.02)^0
f(0) = 10(1)
f(0) = 10
The y-intercept represents the height of the plant when they began the experiment.
f(1) = 10(1.02)^1
f(1) = 10(1.02)
f(1) = 10.2
(1, 10.2)
f(5) = 10(1.02)^5
f(5) = 10(1.1040808)
f(5) = 11.040808
f(1)=10(1.02)^1
f(1)=10.2
Average rate= (fn2-fn1)/(n2-n1)
=11.04-10.2/(5-1)
=0.22
the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.