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2 years ago

-5/6x=20 it needs to be simplifyedplz explain step by step plz help

Mathematics

1 answer:

ryzh [129]2 years ago

4 0

Answer:

$\displaystyle -24 = x$

Step-by-step explanation:

$\displaystyle \frac{-\frac{5}{6}x}{-\frac{5}{6}} = \frac{20}{-\frac{5}{6}} \\ \\ x = -24$

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STatiana [176]

Answer:

x=-8

Step-by-step explanation:

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8 0

1 year ago

Read 2 more answers

An evolutionary biologist examined the relative fitness of Escherichia coli bacteria grown for 2000 generations, about 300 days,

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: fitness of a line of E. coli grown on an acidic environment.

n= 6 E. coli lines

Recorded fitness for each line: 1.24, 1.22, 1.23, 1.24, 1.18, 1.09

The relative fitness of 1 indicates that both bacteria types are equally fit.

A relative fitness larger than 1 indicates that the acid-evolved line is more fit than the parental line kept at neutral pH when both are grown in acidic conditions.

Meaning that if the average fitness of the E. coli lines grown on an acidic environment is greater than 1 then they are better adjusted to live in acidic conditions, symbolically: μ > 1

The statistic hypotheses are:

H₀: μ ≤ 1

H₁: μ > 1

α: 0.05

Assuming that the variable has a normal distribution you have to apply a one-sample t-test:

$t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~~t_{n-1}$

X[bar]= 1.20

S= 0.06

$t_{H_0}= \frac{1.20-1}{\frac{0.06}{\sqrt{6} } } = 8.40$

The p-value for this test is 0.0002

Since the p-value= 0.0002 is less than α:0.05 the decision is to reject the null hypothesis.

Then at a 5% significance level, there is significant evidence to conclude that the bacteria evolved in acidic pH are better adapted to acidic conditions.

I hope you have a SUPER day!

7 0

2 years ago

The daily demand for ice cream cones at a price of $1.20 per cone is 50 cones. At a price of $2.20 per cone, the demand is 30 co

Lapatulllka [165]

Answer:

<h2>The demand at a price of $1.50 per cone is 44 cones</h2>

Step-by-step explanation:

let us apply the interpolation formula to solve this problem

we have

$\frac{y-y1}{x-x1} =\frac{y2-y1}{x2-x1}$

Now let us set the values to the notation above

x= $1.20

x1= $2.20

x2= $1.50

y = 50 cones

y1= 30 cones

y2= ?

$y2= \frac{(y-y1)}{(x-x1)} (x2-x1)+y1$

Substituting our given data we have

$y2= \frac{(50-30)}{(1.2-2.2)} (1.5-2.2)+30\\\\y2= \frac{20}{-1} (-0.7)+30\\\\y2= (20*0.7)+30\\y2= 14+30\\y2= 44$

the demand at a price of $1.50 per cone is 44 cones

4 0

2 years ago

If cos θ = .62 and if 0<θ<90 what is the approximate value of sin θ to the nearest hundredth

Deffense [45]

$\cos\Theta=0.62\\\\\text{Use:}\ \sin^2\alpha+\cos^2\alpha=1\\\\\sin^2\Theta+(0.62)^2=1\\\\\sin^2\Theta+0.3844=1\ \ \ |-0.3844\\\\\sin^2\Theta=0.6156\to\sin\Theta=\pm\sqrt{0.6156}\\\\\sin\Theta_1\approx-0.78\ \vee\ \sin\Theta\approx0.78\\\\\Theta\in(0^o;\ 90^o),\ therefore\ \sin\Theta \ \textgreater \ 0\to\boxed{\sin\Theta\approx0.78}$

5 0

2 years ago

Please help me now :c

nadya68 [22]

On Monday he reads 2 pages, on Tuesday he reads 6 pages (triple of 2: 2 + 2 + 2 = 6), on Wednesday he reads 18 pages (triple of 6: 6 + 6+ 6 = 18), on Thursday he reads 54 pages (triple of 18: 18 + 18 + 18 = 54).

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2 years ago