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3 years ago

How many triangles can be drawn with side lengths 3ft, 4ft, and 5ft

Mathematics

1 answer:

AleksandrR [38]3 years ago

6 0

Answer:

Step-by-step explanation:

The way to figure out if it is a triangle or not is by using the triangle inequality theorem. It says that the sum of 2 sides of the triangle must be larger than the third side. Therefore, there are 3 triangles that we can make with the side lengths of 3ft, 4ft, and 5ft.

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How would you graph 2y-4x=104 as y=mx+b

ANTONII [103]

Answer:

y=-2x+52

Step-by-step explanation:

subtract -4 to the other side wich make the equation 2y=-4x+104 then just divide 2 with -4xand104 wich makes y=-2x+52

4 0

3 years ago

To obtain an estimate of the proportion of "full time" university students who have a part time job in excess of 30 hours per we

musickatia [10]

Answer:

2,436 students

Step-by-step explanation:

At a 90% confidence level, the z-score is 1.645 and the confidence interval is given by:

$x\pm z\frac{s}{\sqrt n}$

Where s is the standard deviation, and n is the sample size.

If they want the length of their confidence interval to be no greater than 0.2, it must be no further than 0.1 from the mean 'X':

$0.1>1.645\frac{3}{\sqrt n}\\\sqrt n>1.645*30\\n>2,435.42$

Rounding up to the next whole number, the sample size should be 2,436 students.

5 0

4 years ago

Help with numer 5 please. thank you

Alex17521 [72]

Answer:

See Below.

Step-by-step explanation:

We are given that:

$\displaystyle I = I_0 e^{-kt}$

Where I₀ and k are constants.

And we want to prove that:

$\displaystyle \frac{dI}{dt}+kI=0$

From the original equation, take the derivative of both sides with respect to t. Hence:

$\displaystyle \frac{d}{dt}\left[I\right] = \frac{d}{dt}\left[I_0e^{-kt}\right]$

Differentiate. Since I₀ is a constant:

$\displaystyle \frac{dI}{dt} = I_0\left(\frac{d}{dt}\left[ e^{-kt}\right]\right)$

Using the chain rule:

$\displaystyle \frac{dI}{dt} = I_0\left(-ke^{-kt}\right) = -kI_0e^{-kt}$

We have:

$\displaystyle \frac{dI}{dt}+kI=0$

Substitute:

$\displaystyle \left(-kI_0e^{-kt}\right) + k\left(I_0e^{-kt}\right) = 0$

Distribute and simplify:

$\displaystyle -kI_0e^{-kt} + kI_0e^{-kt} = 0 \stackrel{\checkmark}{=}0$

Hence proven.

4 0

3 years ago

What ja the slope intercept form of (-6,-3) and (-9,-2)

Y_Kistochka [10]

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6 0

3 years ago

How do I simplify the expression 7^0+7^2 over (7^3)^2

AlekseyPX

$\frac{7^0+7^2}{(7^3)^2}=\frac{1+49}{7^6} = \frac{50}{117649}$

Ok done. Thank to me :>

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2 years ago