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Natalka [10]
3 years ago
13

Suppose △jcd≅△may△jcd≅△may. which other congruency statements are correct? select each correct answer.

Mathematics
2 answers:
stepan [7]3 years ago
8 0
Remember that congruent mean the length and the side of the shape is exactly identical. Based on that, i think the answers would be :

a. △cjd≅△amy△cjd≅△amy 
b. △dcj≅△yam△dcj≅△yam 

Hope this helps
sveta [45]3 years ago
4 0

The <em><u>correct answers</u></em> are:

a. △cjd≅△amy; and b. △dcj≅△yam

Explanation:

If two triangles are congruent, this means that all corresponding angles of one triangle are congruent to corresponding angles of the second triangle, and all corresponding sides of one triangle are congruent to corresponding sides of the second triangle.

We are given the statement  △jcd≅△may.  This makes the corresponding angles j and m; c and a; and d and y.

This means that △cjd would need to be congruent to △amy, since the angles match up.

This also means that △dcj would need to be congruent to △yam, since the angles match up.

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Mary has 12 friends, and a total of 13 people including her. Or, she has 25 friends, and a total of 26 people including her.

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First, we know that 26 is divisible by 1, 2, 13, and 26 because (2x13) and (1x26) both equal 26 but we know that Mary has more than 1 friend and if Mary is also added to the group where the candy is divided, that means that 1 and 2 are both out because Mary has more than 1 friend so 1 cannot be the answer and if Mary has 2 friends, that means that the candy would have to be divided 3 ways which is not possible evenly so the answer is either 12 friends or 25 friends.

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Answer:

The answer to the question is

The ratio of the two gas pressures   \frac{P_{x} }{P_{y} } , that is Px to Py = 1/6

Step-by-step explanation:

Let the gases Volumes be V₁ and V₂

Where volume of X = V₁ and

volume of Y = V₂

The volume of Y is half the volume of X

∴ V₂  =  \frac{1}{2} × V₁

Let the number of moles be n₁ and n₂ in X and Y respectively

therefore  n₂ = 3 × n₁

The pressure of the gas in X is Pₓ and the pressure of the gas in Y is  P_{y} then we have

P₁ × V₁  = n₁ × R × T₁ , and P₂ × V₂ = n₂ × R × T₂

(P₁ × V₁)/(n₁ × T₁) = (P₂ × V₂)/(n₂ × T₂)

but T₁ = T₂

Therefore

(P₁ × V₁)/n₁ = (P₂ × V₂)/n₂.  However  n₂ = 3 × n₁  and V₂  =  \frac{1}{2} × V₁ therefore substituting in the equation we have

(P₁ × V₁)/n₁ = (P₂ ×  \frac{1}{2} × V₁ )/(3 × n₁) from where

P₁ /P₂ =  (\frac{1}{2} × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6

The ratio of \frac{P_{x} }{P_{y} } = 1/6

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4 years ago
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