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tia_tia [17]
3 years ago
14

Find the exact values ofcos (3pi/4radians) and sin (3pi/4 Radians)

Mathematics
1 answer:
allsm [11]3 years ago
7 0
\cos\dfrac{3\pi}{4}=\cos\left(\pi-\dfrac{\pi}{4}\right)=-\cos\dfrac{\pi}{4}=-\dfrac{\sqrt2}{2}

\sin\dfrac{3\pi}{4}=\sin\left(\pi-\dfrac{\pi}{4}\right)=\sin\dfrac{\pi}{4}=\dfrac{\sqrt2}{3}

Look at the picture.

\dfrac{\pi}{2} \ \textless \  \dfrac{3\pi}{4} \ \textless \  \pi\\\\therefoere\\\\\cos\dfrac{3\pi}{4} \ \textless \  0\ and\ \sin\dfrac{3\pi}{4} \ \textgreater \  0

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What is the reasonable estimate for -3/2 x -5 1/4
Lady bird [3.3K]

Answer:

7.875......7.9.....or 8

Step-by-step explanation:

-3÷2×-21÷4= 7.875

63÷8=7.875

3 0
3 years ago
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Find the center and the radius of the circle with the equation x^2 -2x+y^2 +4y +1
steposvetlana [31]

Answer:

Center = ( 1,-2)

radius = 2

6 0
3 years ago
Can you find the missing angles?
Nitella [24]
Every triangle has 180 degrees when you add there angles so you know that they will add up to 180
they are right triangles so the right angle has 90 degrees 
so for the yellow triangle 
90+45+x=180
135+x=180
45=x
we can tell where the purple and yellow triangle touch is 90 so 45+x=90 to find that angle which is 45
and the other one is 45 
so there are two 90 degree angles and three 45 degree angles.
I hope that made sence
5 0
3 years ago
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Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
Zigmanuir [339]
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.

49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52

For the median you want o line all of your number up from least to greatest and then find the middle number.

49,49,49,52,54,55,55

Your median is 52

The mode is the number that is listed most often

49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times

So, your mode is 49




4 0
3 years ago
Which of the following is not equal to sin⁡(-230°)?
xenn [34]

From trigonometry we know that:

if sin(\theta)=sin(\alpha)

then, \theta=n\pi+(-1)^n\alpha (where n is an integer)

This can be rewritten in degrees as:

\theta=n(180^{\circ})+(-1)^n\alpha.............(Equation 1)

Now, in our case, \alpha=-230^{\circ}

Therefore, (Equation 1) can be written as:

\theta=n(180^{\circ})+(-1)^n(-230^{\circ})..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of \theta that match.

For n=2, (Equation 2) gives us: \theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}.

Thus, sin(230^{\circ})=sin(130^{\circ})

Now, we know that: -sin(-50^{\circ})=sin(50^{\circ})

Let n=-1, then:

\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}

Thus, sin(-230^{\circ})=-sin(-50^{\circ})

Likewise, sin(-230^{\circ})=sin(50^{\circ})

Only the last option sin(-50^{\circ}) will never match sin(-230^{\circ}) because no integral value of n will ever give \theta=-50^{\circ}

Thus the last option is the correct option.

3 0
2 years ago
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