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castortr0y [4]
2 years ago
13

For triangle ABC with sides a,b and c the law of cosines states

Mathematics
1 answer:
grigory [225]2 years ago
6 0

Answer:

SAS

Step-by-step explanation:

Looking for the third side given the other two sides and the angle between them

c² = a² + b² - 2abcosC

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The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for m^{2} +1 is 9.

Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and \sqrt{t-1} for 8<t<11.

A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.

B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.

C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.

D) In this we have to find the function at m^{2} +1 when m belongs to \sqrt{7} and \sqrt{10} the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.

Learn more about functions at brainly.com/question/10439235

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Step-by-step explanation:

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