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3 years ago

Two numbers, 3 and a, have a geometric mean of 9. Find the value of a.

1 answer:

4 0

The geometric mean of two numbers x and y is √(xy).

So, if the geometric mean of 3 and a is 9 =>

9 = √(3a)

=> 9^2 = 3a

=> a = 9^2 / 3

a = 81 / 3

a = 27

Answer: the value of a is 27.

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I require assistance with this math problem

grigory [225]

Answer:

Step-by-step explanation:

Since RQ bisects WRV, WRQ = QRV, 48=7y+6. 48-6=42, leaving 42=7y. 42/7=6.

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2 years ago

Will give brainliest answer

makvit [3.9K]

Answer:

$28 . 26cm$

Step-by-step explanation:

First find the radius

$d = 2r \\ 9 = 2r \\ \frac{9}{2} = \frac{2r}{2} \\ r = 4.5$

Now find the CIRCUMFERENCE

$c = 2\pi \: r \\ = 2 \times \pi \times 4.5 \\ = 9 \times \pi \\ = 28.26$

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3 years ago

Find the equivalent exponential expression. [(-4)^5]^3

Sunny_sXe [5.5K]

Answer:

$-4^{15}$

Step-by-step explanation:

Given expression:

$\left[(-4)^5\right]^3$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\implies (-4)^{(5 \times 3)}$

$\implies (-4)^{15}$

$\textsf{Apply exponent rule} \quad (-a)^n=-a^n,\:\: \textsf{ if }n \textsf{ is odd}:$

$\implies -4^{15}$

4 0

1 year ago

C. If a < 0 and f(a) > 0, then the point (a, f(a))

professor190 [17]

The answer is: b - lies in quadrant II when graphed.

Explanation:

Any number less than zero is a negative number.

Example: -1

Any number greater than zero is a positive number.

Example: 1

(a, f(a))

(-1,1)

When these example points are graphed, they are placed in the second quadrant.

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2 years ago

Which equations have no real solution but have two complex solutions?

agasfer [191]

Answer:

Here you go - IM NOT 100% SURE THESE ARE RIGHT

Step-by-step explanation:

1. 2 complex solutions

2. 1 complex solution

3. 1 complex solution

4. no complex solutions

7 0

3 years ago