Salt is used in the largest quantity in Lydia's recipe.
<em><u>Explanation</u></em>
Required spices are......
Salt =
teaspoon , Oregano =
teaspoon, Crushed thyme =
teaspoon and Black peeper =
teaspoon
For finding the largest quantity, first we need to make the denominators of each fraction as equal and then identify the largest numerator.
The denominators are 2, 3, 4 and 8 and their LCM(Least common multiple) will be 24. So.....

As the largest numerator is 12 here, so the value of
is largest among all the fractions.
Thus, <u>Salt</u> is used in the largest quantity in Lydia's recipe.
Answer:
The answer is $28.56
Step-by-step explanation:
To find the 2% sales tax, you need to multiply the 2% or 0.02 by 28.
Doing this will give you 0.56.
Then you add 0.56 to 28 to get 28.56, hence, $28.56 is the total cost.
Hope it helps!
Tan46=x/12
12×tan 46=x
12×1.03=x
0.21255=x
Answer:
c. Cluster sampling
Step-by-step explanation:
Taking into account that the exercise researcher is looking with limited resources to study a population that is divided, her best option is cluster sampling, which is a method applicable to this type of population, we could select in each group randomly her sample, the observational study is discarded because she does not have much availability of time or resources, nor would the stratified study be useful because she should select subgroups and create them to take samples and this would take more time and resources and sampling systematic is not adequate because it must have all the individuals and after having the list select the sample, but as we know, it is a process that will study the number of individuals so this option is not feasible.
For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>