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anygoal [31]
2 years ago
8

The solution set of x(x-5) is greater than or equal to 0 is

Mathematics
1 answer:
kompoz [17]2 years ago
6 0
Solve x(x-5)=0; the roots are 0 and 5.

Draw a number line.  Plot 0 and 5 on this line.  
Set up 3 intervals, as follows:  (-infinity, 0), (0, 5), and (5, infinity).

Now choose a test number from within each interval (e. g., -2, 3, 10).

Subst. each into the inequality x(x-5)\geq 0.  In each case, determine whether the inequality is true or false.  

Based upon your results here, you should be able to determine on which interval or intervals the inequality is true.  Those interval(s) is/are your solution set.
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Solve each inequality, graph the solution on the number line, and write the solution in interval notation
Lubov Fominskaja [6]

Answer:

(-\infty,+\infty)

Step-by-step explanation:

The given inequality is 3x-2>4 or 5x-3\leq 7

We group similar terms to obtain: 3x>4+2 or 5x\le7+3

Simplify to get:

3x>6 or 5x\le10

x>2 or x\le 2

This implies that the solution set is all real numbers.

The solution in interval notation is (-\infty,+\infty)

5 0
3 years ago
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erik [133]

Answer:

fr

Step-by-step explanation:

7 0
3 years ago
What is the exact product of 379 and 8
nadya68 [22]
The product of 379 and 8 is 3,032
8 0
3 years ago
You pay a company $2400 for online promotion which increases your profit by $25,456. What percent did it increase?
MA_775_DIABLO [31]
Your profit increased by about 1061%
6 0
2 years ago
Help me I’m dumb and stupid :)
wel

Answer:

The first digit of the quotient should be placed at the leftmost place of the places of the all the digits in the quotient.This is so from the basic rule of division.

Step-by-step explanation:

The quotient is given by,

[\frac {4,839}{15}] [where [x] is the greatest integer function on x]

= [322.6]

= 322

and the remainder is given by,

15 \times 0.6

= 9

So, the first digit of the quotient should be placed at the leftmost place of the places of the all the digits in the quotient and this is so from the very basic rule of division.

8 0
2 years ago
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