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3 years ago

The solution set of x(x-5) is greater than or equal to 0 is

1 answer:

6 0

Solve x(x-5)=0; the roots are 0 and 5.

Draw a number line. Plot 0 and 5 on this line.
Set up 3 intervals, as follows: (-infinity, 0), (0, 5), and (5, infinity).

Now choose a test number from within each interval (e. g., -2, 3, 10).

Subst. each into the inequality x(x-5) $\geq$ 0. In each case, determine whether the inequality is true or false.

Based upon your results here, you should be able to determine on which interval or intervals the inequality is true. Those interval(s) is/are your solution set.

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Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both insp

Yuliya22 [10]

Complete question is;

Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both inspectors). The first inspector detects 83% of all defectives that are present, and the second inspector does likewise. At least one inspector does not detect a defect on 34% of all defective components. What is the probability that the following occurs?

(a) A defective component will be detected only by the first inspector?

b) A defective component will be detected by exactly one of the two inspectors?

(c) All three defective components in a batch escape detection by both inspectors (assuming inspections of different components are independent of one another)?

Answer:

A) 0.17

B) 0.34

C) 0

Step-by-step explanation:

a) We are told that the first inspector(A) detects 83% of all defectives that are present, and the second inspector(B) also does the same.

This means that;

P(A) = P(B) = 83% = 0.83

We are also told that at least one inspector does not detect a defect on 34% of all defective components.

Thus;

P(A' ⋃ B') = 0.34

Also, we now that;

P(A ⋂ B) = 1 - P(A' ⋃ B')

P(A ⋂ B) = 1 - 0.34

P(A ⋂ B) = 0.66

Probability that A defective component will be detected only by the first inspector is;

P(A ⋂ B') = P(A) - P(A ⋂ B)

P(A ⋂ B') = 0.83 - 0.66

P(A ⋂ B') = 0.17

B) probability that a defective component will be detected by exactly one of the two inspectors is given as;

P(A ⋂ B') + P(A' ⋂ B) = P(A) + P(B) - 2P(A ⋂ B)

P(A) + P(B) - 2P(A ⋂ B) ; 0.83 + 0.83 - 2(0.66) = 0.34

C) Probability that All three defective components in a batch escape detection by both inspectors is written as;

P(A' ⋃ B') - (P(A ⋂ B') + P(A' ⋂ B))

Plugging in the relevant values, we have;

0.34 - 0.34 = 0

7 0

3 years ago

Which situation shows the appropriate use of the law of large numbers? . a. Wilma predicts rolling a 2 about 50 times if she rol

Nata [24]

"<span>Wilma predicts rolling a 2 about 50 times if she rolls a die 300 times" is the one situation among the following choices given in the question that shows the </span><span>appropriate use of the law of large numbers. The correct option among all the options that are given in the question is the first option or option "a". I hope it helped you.</span>

7 0

3 years ago

Wil someone help me convert all of these to metric, for those that can be.

iren2701 [21]

Approximate conversions for cooking are ...

1 tsp ≈ 5 mL, so 1/2 tsp is about 2.5 mL

1 Tbsp ≈ 15 mL

1 cup ≈ 240 mL, so 1 1/2 cups ≈ 355 mL*

1 1/2 lb ≈ 680 g

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* 1 cup is about 236.6 mL.

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