Answer:
Step-by-step explanation:
The given inequality is 3x-2>4 or
We group similar terms to obtain: 3x>4+2 or
Simplify to get:
3x>6 or
x>2 or
This implies that the solution set is all real numbers.
The solution in interval notation is
The solution set of x(x-5) is greater than or equal to 0 is
1 answer:
Solve x(x-5)=0; the roots are 0 and 5.
Draw a number line. Plot 0 and 5 on this line.
Set up 3 intervals, as follows: (-infinity, 0), (0, 5), and (5, infinity).
Now choose a test number from within each interval (e. g., -2, 3, 10).
Subst. each into the inequality x(x-5)
0. In each case, determine whether the inequality is true or false.
Based upon your results here, you should be able to determine on which interval or intervals the inequality is true. Those interval(s) is/are your solution set.
Draw a number line. Plot 0 and 5 on this line.
Set up 3 intervals, as follows: (-infinity, 0), (0, 5), and (5, infinity).
Now choose a test number from within each interval (e. g., -2, 3, 10).
Subst. each into the inequality x(x-5)
Based upon your results here, you should be able to determine on which interval or intervals the inequality is true. Those interval(s) is/are your solution set.
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Answer:
The first digit of the quotient should be placed at the leftmost place of the places of the all the digits in the quotient.This is so from the basic rule of division.
Step-by-step explanation:
The quotient is given by,
[where [x] is the greatest integer function on x]
= [322.6]
= 322
and the remainder is given by,
= 9
So, the first digit of the quotient should be placed at the leftmost place of the places of the all the digits in the quotient and this is so from the very basic rule of division.