I need the answer to the problem

F(x) = 2x – 1 g(x) = 7x – 12 What is h(x) = f(x) + g(x)?

WINSTONCH [101]

Answer:

Solution,

 $h(x) = f(x) + g(x) \\ \: \: \: \: \: \: \: = 2x - 1 + 7x - 12 \\ \: \: \: \: \: \: = 2x + 7x - 1 - 12 \\ \: \: \: \: \: \: = 9x - 13$ 

hope this helps...

Good luck on your assignment..

4 0

3 years ago

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Please help me ! Today 11/6/2020 :(

dangina [55]

I believe the answer is c, TSR

5 0

3 years ago

Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers

Mars2501 [29]

Answer:

a) Let $\frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}$ .

Observe that

$\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

b)

Let $\frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.$

Observe that

$\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

c)

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.$

Observe that

$\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}$

d)

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.$

Observe that

$\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}$

3 0

3 years ago

A computer uses 1/200 second of a secount to finish a math problem . How many math questions can the computer solve in 2 minutes

aniked [119]

Answer: The computer can solve 24,000 math problems in 2 minutes.

Step-by-step explanation:

1.) Multiply 1 * 200, in order to get the amount of problems solved in a second, which would be 200.

2.) Multiply 200 * 60 to get the amount of problems solved in a minute, which would be 12,000.

3.) Multiply 12,000 * 2 in order to get the amount of problems solved in 2 minutes, which would be 24,000.

4 0

3 years ago

One number is five more than three times another. If their difference is 35, what is the larger number?

miv72 [106K]

Let x and y be the two unknown numbers. If one number, say x,is 5 more than 3 times another, say y, the equation would be

x = 5 + 3y

When their difference is 35, x-y = 35, since x is the much larger number here. We substitute x to solve for the smaller number, y.

x - y = 35
(5 + 3y) -y = 35
5 +2y = 35
2y = 35-5
2y = 30
y = 15

The larger number x would be
x = 5 + 3(15)
x = 50

The answer is 50.

8 0

3 years ago

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