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gulaghasi [49]
3 years ago
6

I need the answer to the problem

Mathematics
1 answer:
zubka84 [21]3 years ago
8 0
I hope this helps you

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The sum of two numbers is 120. Three times
alexgriva [62]

Answer:

The answer is 68 and 52

Step-by-step explanation:

x + y = 120

3(x - y ) = 48

We have 3x + 3y = 360

and 3x - 3y = 48

Adding we have the following:

6x = 408

x = 68

y = 120-48 = 52

6 0
3 years ago
Kathy buys a bicycle after a 30% markdown. The original price was $490.00. What did<br> she pay?
Umnica [9.8K]

Answer:

$343

Step-by-step explanation:

To get 30% of 490 we divide 30% by 1

30% ÷ 1 = 147

Now, we subtract 490 by 147

490 - 147 = 343

4 0
3 years ago
Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
2 years ago
Solve the inequality r 4-2(r-14)&gt;0
klasskru [66]
R^4-2(r-14)>0
r^4-2r+28>0
r^4-2r+28=0
There is no real solution but there is all real numbers
:)
4 0
3 years ago
Write as a fraction.
lesantik [10]

Answer:

the answer is 5/8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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