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3 years ago

I need the answer to the problem

Mathematics

1 answer:

zubka84 [21]3 years ago

8 0

I hope this helps you

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The sum of two numbers is 120. Three times

alexgriva [62]

Answer:

The answer is 68 and 52

Step-by-step explanation:

x + y = 120

3(x - y ) = 48

We have 3x + 3y = 360

and 3x - 3y = 48

Adding we have the following:

6x = 408

x = 68

y = 120-48 = 52

6 0

3 years ago

Kathy buys a bicycle after a 30% markdown. The original price was $490.00. What did<br> she pay?

Umnica [9.8K]

Answer:

$343

Step-by-step explanation:

To get 30% of 490 we divide 30% by 1

30% ÷ 1 = 147

Now, we subtract 490 by 147

490 - 147 = 343

4 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

Solve the inequality r 4-2(r-14)>0

klasskru [66]

R^4-2(r-14)>0
r^4-2r+28>0
r^4-2r+28=0
There is no real solution but there is all real numbers
:)

4 0

3 years ago

Write as a fraction.

lesantik [10]

Answer:

the answer is 5/8

Step-by-step explanation:

8 0

3 years ago

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