Answer:
- Code is in JAVA language. As there is no user input the logic is straightforward.
- Below is the code along with a detailed explanation of the logic.
- The class name is Print main save as file as the main class.
Explanation:
Program:-
public class Main{
public static void main(String args[]){
/* There are two for loops...
* First for loop runs from i=1 to i=9
* Second for loop runs from j=1 to j=i.
*
*/
for(int i=1;i<=9;i++){
for(int j=1;j<=i;j++){ // j loop runs from j=1 to j=i
/*Prints I and j next to each other*/
System.out.println(i+""+j);
}//for loop of j ends here
}// for loop of I ends here
}
}
Answer:
No. This is not more secure.
Explanation:
this is not more secure than having all of Carol, bob and Alice having the same key.
alice would be able to know Carol's key for her to be able to verify the answer Carol gave to a challenge by her. she would also have to know bob's key to do the same.
any of these 3 would have to know someone else's secret key to verify answers to any challenge.
the challenge is to know the secret keys if the other two and if done, decryption can easily be done and they can impersonate.
Answer:
The answer is "Option c"
Explanation:
The W3C is the framework for the creation of software and the online standards through which sites and webpages work, and to turn into an authoritative source of information, she will work towards getting a reliable and credible source of knowledge from the "World Wide Web Consortium", and the wrong option can be described as follows:
- In option a, It is wrong because this organization prepares and publishes all the electronic technologies.
- In option b, It is wrong because it is the laboratory of physics, which is not useful in web development.
- In option d, This technology is used in TCP/IP protocol, that's why it is incorrect.
Answer:
There is nothing please put it then i will edit this answer.
Explanation:
Every application has access to specific opened port. If you only make a exception for the specific application only that application can bypass the firewall.
