Answer:
The missing part of the code is:
for (i = 0; i < courseGrades.length; ++i) {
System.out.print(courseGrades[i]+" "); }
System.out.println();
for (i = courseGrades.length-1; i >=0 ; --i) {
System.out.print(courseGrades[i]+" "); }
System.out.println();
Explanation:
This iterates through the array
for (i = 0; i < courseGrades.length; ++i) {
This prints each element of the array followed by a space
System.out.print(courseGrades[i]+" "); }
This prints a newline at the end of the loop
System.out.println();
This iterates through the array in reverse
for (i = courseGrades.length-1; i >=0 ; --i) {
This prints each element of the array (reversed) followed by a space
System.out.print(courseGrades[i]+" "); }
This prints a newline at the end of the loop
System.out.println();
Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
