Answer: Reusing software device has some economical challenges such as:
- Investment cost in reusing the device is considered as the extra cost.It might require some extra components for the working to become usable
- Requires skilled person who can develop and design the software to be used again.The creating and designing of new software design is comparatively easy but making the system reusable requires someone who has more designing skill who will be highly paid for the work
- Cost of writing and reading of the software can also be considered as the economical challenge as the reused system created is to be studied by some other organization members or sources not familiar with the functioning. .
Answer:
Following is the detailed answer as needed.
<h3>I hope it will help you!</h3>
Explanation:
Data sharing, maintaining security
<u>Explanation:</u>
Kristian is a cybersecurity professional. She is writing a book called The Door Toward Cybersecurity. Organizations should avoid any data <u>sharing or exchange</u> while servers are transmitting information. This will help organizations keep the information intact and maintain <u>security.</u> If any info or data shared when the servers are transmitting the info, then it may lead to the loss of security, and the information gets leaked. So it must be avoided to share while transmission of info using the servers.
Answer:
See explaination
Explanation:
#include <iomanip>
#include <string>
#include <fstream>
using namespace std;
void getName(string);
void getPin(int,int);
void displayMenu(int);
string name;
int pin1, pin2, ch ;
int main()
{
cout << fixed << showpoint << setprecision(2);
getName(name);
getPin(pin1,pin2);
displayMenu(ch );
system("pause");
}
void getName(string name)
{
cout << "Enter your name: ";
cin >> name;
if (name = "AXBY") || (name != "ABGSHY"))
{
getName(name);
}
}
void getPin(int pin1, int pin2)
{
string name;
if (name == "AXBY")
{
cout << "Please Enter Pin: ";
cin >> pin1;
if (pin1 != 4433)
{
cout << "Pin incorrect please try again!";
cin >> pin1;
}
}
if (name == "ABGSHY")
{
cout << "Please Enter Pin: ";
cin >> pin2;
if (pin2 != 2849)
{
cout << "Pin incorrect please try again!";
cin >> pin2;
}
}
}
void displayMenu(int ch )
{
cout << "[1] Check your account Balance\n"
"[2] Withdraw funds\n"
"[3] Deposit funds\n"
"Please Enter Choice: ";
cin >> ch ;
if (ch != 1 || ch != 2 || ch != 3)
{
cout << "Choice is incorrect, enter choice now: ";
cin >> ch ;
}
}
