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postnew [5]
3 years ago
6

Plz help i need help on this i do not get it

Mathematics
2 answers:
Andrej [43]3 years ago
6 0
Area of circle 1 = πr² 
Area of circle 1 = π (10)²
Area of circle 1 = 100π km²

Area of circle 2 = πr²
Area of circle 2 = π (5)²
Area of circle 2 = 25π km²

Number of times the bigger circle is greater than the smaller circle 
\dfrac{100 \pi }{25 \pi } = 4

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Answer: The big circle is 4 times greater than the small circle.
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elena-14-01-66 [18.8K]3 years ago
6 0
We know that the area of a circle is A= \pi r^{2}. The relationship between area and radius is a quadratic relationship. So we know that the ratio of the areas of the circles will be equal to the ratio of the squares of the radii of the circles.

The ratio of the squares of radii between circle 1 and 2 are \frac{10^{2} }{5^{2} }, which is equal to four. Thus, the area of circle 1 is four times larger than the area of circle two.
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A company sells a dried fruit mixture for $5 per pound. To make the mixture, banana chips that cost
ELEN [110]

Answer:

  2.5 pounds

Step-by-step explanation:

Let s represent the number of pounds of dried strawberries that should be added to the bananas. The total cost of the mixture will be ...

  (2.50)(3) +(8.00)(s) = (5.00)(3 +s)

  7.50 +8s = 15 +5s . . . . . . . eliminate parentheses

  3s = 7.50 . . . . . . . . . subtract 7.50+5s

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2.5 pounds of dried strawberries should be added to make the mixture.

6 0
2 years ago
If 1200 cm^2 of material is available to make a box with a square base and an open top find the largest possible volume of the b
strojnjashka [21]
Surface area of box=1200 cm² 
<span>Volume of box=s²h </span>
<span>s = side of square base </span>
<span>h = height of box </span>
<span>S.A. = s² + 4sh </span>
<span>S.A. = surface area or 1200 cm², s²
 = the square base, and 4sh = the four 'walls' of the box. </span>
<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>


<span>v(s) = s²((1200 - s²)/(4s)) </span>
<span>v(s) = s(1200 - s²)/4 . </span>
<span>v(s) = 300s - (1/4)s^3</span>

by derivating
<span>v'(s) = 300 - (3/4)s² </span>
<span>0 = 300 - (3/4)s² </span>
<span>-300 = (-3/4)s² </span>
<span>400 = s² </span>
<span>s = -20 and 20. </span>
again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>


<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
<span>v(s) = 6000 - (1/4)(8000) </span>
<span>v = 6000 - 2000 
v=4000</span>
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2 years ago
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MrRa [10]
B is the answer :)))
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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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Elena L [17]

Answer:

3 and i use flvs too, also that pfp is fire

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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