K (x) = 6x + 100 <br> k(-5) = ?

5) Two machines M1, M2 are used to manufacture resistors with a design

Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that $\mu = 1050, \sigma = 100$

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1100 - 1050}{100}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915.

X = 900

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{900 - 1050}{100}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that $\mu = 1000, \sigma = 120$

X = 1100

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1100 - 1000}{120}$

$Z = 0.83$

$Z = 0.83$ has a pvalue of 0.7967.

X = 900

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{900 - 1000}{120}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0

3 years ago

In the bronze medal game of the 2014 FIBA Asia Cup, and with his team down by two points, Philippines guard Paul Dalistan was fo

dsp73

Complete Question

Question: In the bronze medal game of the 2014 FIBA Asia Cup... In the bronze medal game of the 2014 FIBA Asia Cup, and with his team down by two points, Philippines guard Paul Dalistan was fouled while attempting a three-pointer at the buzzer. He missed the shot and headed to the line for three foul shots.

1. Watch the video of Dalistan preparing to take his first shot. Before he shoots, what is the probability that Philippines will win the game? Lose the game? Send it into overtime? Dalistan’s free throw percentage is 84.6%

Answer:

a

The probability that Philippines will win the game is $P(A) = 0.6055$

b

The probability that Philippines will lose the game is $P(B) = 0.00365$

c

The probability that the game will be sent to overtime is $P(C) = 0.06$

Step-by-step explanation:

From the question we are told that

The probability of Paul Dalistan making a shot is p = 0.846

The probability of Paul Dalistan not making the shot is $q = 1- p = 1- 0.846=0.154$

Paul Dalistan team was down by two points

This mean that for Paul Dalistan's team to win the game he must make the 3 free throws

So the probability that Philippines will win the game is mathematically represented as

$P(A) = p^3$

=> $P(A) = 0.846^3$

=> $P(A) = 0.6055$

Gnerally for Paul Dalistan's team to loss the game it means that Paul Dalistan did not make any of the free shot

Hence the probability that Philippines will loss the game is

$P(B) = q^3$

=> $P(B) = (0.154 )^3$

=> $P(B) = 0.00365$

Generally for the game to be sent to overtime then the game must be tied and for the game to be tied, Paul Dalistan have to make 2 out of the three shots

Hence the probability that game will go to overtime is

$P(C) = 3 * 0.846 * 0.154 * 0.154$

$P(C) = 0.06$

6 0

3 years ago

The sum of three consecutive even numbers is 48. What is the biggest of these numbers?

Luden [163]

Answer:

The greatest number is 18.

Step-by-step explanation:

consecutive: following one after the other

48 ÷ 3 = 16

16 would be the middle number

14 : 16 : 18

14 = smallest number

16 = middle number

18 = biggest number

14 + 16 + 18 = 48

3 0

3 years ago

Using the distributive property to find the product (y – 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y

Travka [436]

( y - 4 ) ( y² + 4 y + 16 ) =
= y³ + 4 y² + 16 y - 4 y² - 16 y - 64 = y³ - 64
If the result is the polynomial of the form:
y³ + 4 y² + a y - 4 y² - a y - 64
a = 16

8 0

3 years ago

HELPPP only got 43 minutes to answer questions

irga5000 [103]

Answer:

20 feet below sea level

Step-by-step explanation:

6 0

2 years ago

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K (x) = 6x + 100 k(-5) = ?