T<span>he mean of a sampling distribution of a sample with proportion, p and sample size, n is given by

.
</span>T<span>he standard deviation of a sampling distribution of a sample with proportion, p and sample size, n is given by

</span>Given that t<span>he
manufacturers of m&m's claim that 20% of the milk chocolate m&m
candies are orange. The proportion is p = 0.2
The mean of the
sampling distribution of the sample proportion of orange m&m's for
samples of size 100 is given by

</span><span>The standard deviation of the
sampling distribution of the sample proportion of orange m&m's for
samples of size 100 is given by

</span>
19.32=density D=m÷v so, v=m÷d
v=575÷19.32 v=about 29.8
37 divided by 100 is .37 you move the . over 1 number for every 0
14/x = 1/2
Cross multiply, which is: a/b = c/d ⇒ ad = bc
After cross multiplying, we get:
x = 2(14)
x = 28
Your final answer is C. 28<span>.</span>
Answer: 20.1866666667 as a mixed number is 20 14/75
Step-by-step explanation: