We have that
y=6^x
we know
to find the inverse
replace x with y and y with x,
x=6^y
we know that
y=logb(x)----------> x=b^y
therefore
x=6^y---------------> y=log6(x)
the answer is the option A.) Y=log 6x
Answer:
x <u>></u> 15
Step-by-step explanation:
4(x + 15) <u>></u> 120
Divide by 4
x + 15 <u>></u> 30
Subtract 15
x <u>></u> 15
Answer:
7p¹⁵/ 3q¹²
Step-by-step explanation:
From the question given above,
28p⁹q¯⁵ / 12p¯⁶q⁷
To know which of option is equivalent to the above expression, we shall simplify the expression as shown below:
28p⁹q¯⁵ / 12p¯⁶q⁷
28p⁹q¯⁵ ÷ 12p¯⁶q⁷
Recall:
Xᵐ ÷ Xⁿ = Xᵐ ¯ ⁿ
Therefore,
28p⁹q¯⁵ ÷ 12p¯⁶q⁷ = (28/12)p⁹ ¯ ¯⁶q¯⁵ ¯⁷
28p⁹q¯⁵ ÷ 12p¯⁶q⁷ = (7/3) p⁹⁺⁶q¯¹²
28p⁹q¯⁵ ÷ 12p¯⁶q⁷ = (7/3) p¹⁵q¯¹²
Recall:
X¯ⁿ = 1/Xⁿ
Therefore,
(7/3) p¹⁵q¯¹² = (7/3) p¹⁵ × 1/q¹²
(7/3) p¹⁵q¯¹² = 7p¹⁵/ 3q¹²
Hence,
28p⁹q¯⁵ / 12p¯⁶q⁷ = 7p¹⁵/ 3q¹²
Answer:
easy
Step-by-step explanation:
113.1cm2 squared. Vvvvvvvvvvvvgghfhf
