In don't understand how to work this problem out

Mathematics

1 answer:

andrezito [222]3 years ago

4 0

$x^2+8x-11=\\
x^2+8x+16-27=\\
(x+4)^2-27=\\
(x+4-\sqrt{27})(x+4+\sqrt27)=\\
(x+4-3\sqrt{3})(x+4+3\sqrt3)$

$x^2+6x-11=\\
x^2+6x+9-20=\\
(x+3)^2-20=\\
(x+3-\sqrt{20})(x+3+\sqrt{20})=\\
(x+3-2\sqrt5)(x+3+2\sqrt5)$

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Can't figure it out!!

Zanzabum

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \cfrac{1}{x} \qquad 
\begin{cases}
x_1=2\\
x_2=b
\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}
\\\\\\
\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}
\\\\\\
$

$\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
\\\\\\
2b^2-4b-10b+20=0\implies 2b^2-14b+20=0
\\\\\\
b^2-7b+10=0\implies 
(b-2)(b-5)=0\implies b=
\begin{cases}
\boxed{5}\\
2
\end{cases}$

8 0

3 years ago

Help NO LINKS PLZ thx u.

andrey2020 [161]

Answer:

5, -5

Step-by-step explanation:

well 5-5 is 0 so that's it

:))))

6 0

3 years ago

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