Answer:
1047 cards
Step-by-step explanation:
3x349=1047 3x300=900 3x40=120 3x9=27 900+120+27=1047
The graph went left 1 and up 6. You could complete the square to find out or just graph it!
Hope this helps!
Answer:
The quadratic equation is x^2 + 4x - 32 = 0
Step-by-step explanation:
(x - 4)(x+8) = 0
x^2 + 4x - 32= 0
Answer:
The solutions are x=1 and x=-2/3
Step-by-step explanation:
we have

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient
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Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares


square root both sides
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


Answer:
Resulting plot in the image attached
Step-by-step explanation:
Start by making a table of (x,y) pairs that satisfy this equation. Notice that two pairs would be enough, but it is always safer to obtain at least three to see them actually "aligned".
We are trying to find values for y when x= 0, 2, and 4 to make our calculations simple:

When x = 0 then:
So we plot the value (0,-3) on the x-y plane.
When x = 2 then:
So we plot the value (2,-2) on the x-y plane.
When x = 0 then:
So we plot the value (4,-1) on the x-y plane.
Please see the points and the resulting line in the image attached