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torisob [31]
3 years ago
11

Select the correct answer. What is the domain of the function f(x) = 4x − 16? all real numbers all positive real numbers all pos

itive real numbers except 4 all positive real numbers except 16
Mathematics
2 answers:
bagirrra123 [75]3 years ago
8 0
Hello!

Since the function has no undefined points or domain constants the answer is all real numbers

The answer is all real numbers

Hope this helps!
nekit [7.7K]3 years ago
5 0
<h3>Answer:</h3>

The domain of the function f(x) is:

All real numbers.

<h3>Step-by-step explanation:</h3>

We are given a linear function f(x) in terms of the variable 'x' as:

f(x)=4x-16

Now we are asked to find the domain of the function f(x).

<em>We know that the domain of a function is the possible set of the x-values where the function is well defined that is the function does not gives a absurd result.</em>

As we know that the polynomial function i.e. here a linear polynomial function is defined all over the real axis and is also continuous there.

The graph of this linear function will be a straight line.

Hence, the domain of the given function f(x) is:

All real numbers.

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8. Temperatures in degrees Celsius (C) may be changed to degrees Fahrenheit (F) by using the formula F = 1.8C + 32º. Find the te
pentagon [3]

Answer:

-40 °F = -40 °C

Step-by-step explanation:

(1) F = 1.8 C + 32

If the Fahrenheit and Celsius temperatures are the same, then

(2)        F = C     Substitute (2) into (1)

           C = 1.8C + 32     Subtract 1.8 C from each side

C – 1.8 C = 32                   Combine like terms

   -0.8C = 32                   Divide each side by -0.8

         C = -32/0.8

(3)      C = -40                  Substitute (3) into (1)

        F = 1.8(-40) + 32

        F = -72 + 32

       F = -40

So, -40 °F = -40 °C

The thermometer below shows that -40 °F = -40 °C.

8 0
3 years ago
Please i need help no links or files give me honest answer thanks!
Digiron [165]

Answer:

D)

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Solve for x:a(a²+b²)x²+b²x-a​
m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a  

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b²  = (b² + 2a²)²

2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

5 0
3 years ago
SOMEONE PLEASE ANSWER THIS CORRECTLY PLEASEEE
GrogVix [38]
You just multiply the numbers and if it’s less than that number you it it in the bud hood this helps!
7 0
2 years ago
Read 2 more answers
You are choosing between two health clubs. Club A offers membership for a fee of $ 28 plus a monthly fee of $ 22. Club B offers
Mazyrski [523]

Answer: 2 months, Total cost= $72

Step-by-step explanation:

Let x denote the number of months then

For Club A fee= 28+22x

For Club B fee= 16+28x

Equating both we get

28 + 22x= 16+28x

28-16= 28-22x

12= 6x

x= 2

So after 2 months the fee will be same i.e. 28+22(2)= $72

8 0
3 years ago
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