Answer:
It would be A!
Step-by-step explanation:
.08 times .50 would be 0.04. (It's a quick way to be able to solve problems similar to that! :)
It's <em>370,000.00000...</em> with as many zeros as you want after the decimal point.
A.) 7^4x = 10
log base 10 (7^4X) = log base 10 (10)
4x log base 10 (7) = 1
4x (0.8451) = 1
3.3804x = 1
x = 0.2958
b.) ln(2) + ln(4x-1) = 5
ln (2 * 4x-1) = 5
ln (8x-2) = 5
log base (3) (8x-2) = 5
e^5 = 8x-2
e^5+2 = 8x
x = 18.8016
Degree days are the difference between the daily temperature mean, (high temperature plus low temperature divided by two) and 65°F. 65°F because we assume that at this temperature we do not need cooling or heating.
In our case the daily mean temperature is 83°F and X is the number of cooling-degree days.
X=83-65
X=18
Answer:
9 × 2^(13)
Step-by-step explanation:
hello :
the nth term is : An =A1 × r^(n-1)
a common ratio is : r and A1 the first term
in this exercice : r= -3-(-7)36/18 = 18/9 =2 A1 = 9
when : n =14 you have the 14rd term A14
A14 = 9 × 2^(14-1) = 9 × 2^(13)