There are 4 consecutive even integers that add up to 268. Which integers are they?

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

4 0

Answer:

4n+ 12 = -268, or 4n = -280, or n = -70. This would imply that the four consecutive ODD integers are -70, -68, -66, -64.

Step-by-step explanation:

Hope this helps :)

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domain: all terms are defined for <em>all real numbers</em>
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Step-by-step explanation:

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$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6$